Solution :
Given that,
t /2,df = 1.669
Margin of error = E = t/2,df * (s /n)
= 1.669 * (6800 / 64)
Margin of error = E = 1418.650
The 90% confidence interval estimate of the population mean is,
- E < < + E
44500 - 1418.650 < < 44500 + 1418.650
43081.350 < < 45918.650
Lower-bound: 43081.350
Upper-bound: 45918.350
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