Homework Answers
From previous part,
SST = 68.002
So,
0.2258 = SSR/SST
SSR = 15.355
MSR = 5.5*2.507 = 13.7885
Hence,
DF(Regression) = 15.355/13.7885 = 1
So,
Total degrees of freedom = 1 + 42 = 43
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Given the following ANOVA table: Source of Degrees of Sum of Mean Sum of F2 VarianceFreedom...
Part of an ANOVA table is shown below. Source of Variation Sum of Squares Degrees of...
Part of an ANOVA table is shown below. Source of Variation Sum of Squares Degrees of Freedom Mean Square F Between Treatments 64 8 Within Treatments (Error) 2 Total 100 The number of degrees of freedom corresponding to between-treatments is a. 3. b. 4. c. 2. d. 18.
3. Consider the partially completed two-way ANOVA summary table. Source Sum of Squares Degrees of Freedom...
3. Consider the partially completed two-way ANOVA summary table. Source Sum of Squares Degrees of Freedom Mean Sum of Squares Factor B Factor A 600 200 Interaction 144 Error 384 Total 1,288 23 The number of Factor A populations being compared for this ANOVA procedure is _ A) 5 B) 7 C) 4 D) 6
21) Consider the partially completed one-way ANOVA summary table. Degrees of Mean Sum Freedom of Squares...
21) Consider the partially completed one-way ANOVA summary table. Degrees of Mean Sum Freedom of Squares Sum of Source Squares Between 330 Within Total 1810 1 16 9 The F-test statistic for this ANOVA procedure is A) 2.33 B) 7.33 C) 5.67 D) 3.67
Mean Square (Variance) Degrees of Sum of Source Freedom Squares Consider an experiment with nine groups, with eight val...
Mean Square (Variance) Degrees of Sum of Source Freedom Squares Consider an experiment with nine groups, with eight values in each. For the ANOVA summary table shown to the right, fill in all the missing results. Among FSTAT ? MSA 22 SSA ? c-1 ? groups Within MSW ? SSW 693 n c groups Total SST ? n-1 2 Complete the ANOVA summary table below. Degrees of Freedom Sum of Mean Square (Variance) MSA 22 Source Squares FSTAT Among groups...
a.) given the following table for a one-way ANOVA test for four treatment groups with six...
a.) given the following table for a one-way ANOVA test for four
treatment groups with six subjects in each group, what would the
decision about H0 be if
?
H0 is ___ @ P ___
Source
Sum of Squares
Degrees of Freedom
Mean Squares
F Ratio
P Value
Treatment
33
Error
Total
145
a-0.05
0.0.2702 QUESTION 17 Consider the following partial ANOVA table. Source of variation df Sum of squares...
0.0.2702 QUESTION 17 Consider the following partial ANOVA table. Source of variation df Sum of squares Mean squares Treatments Error Total 6.67 75 60 19 135 25 3.75 The numerator and denominator degrees of freedom (identified by asterisks) are, respective 1. 4 and 15 2. 3 and 16 3. 15 and 4 4. 16 and 3 5. 4 and 8
Problem 4: Complete the ANOVA table based on the following data: Replications Standard Deviation ...
Problem 4: Complete the ANOVA table based on the following data: Replications Standard Deviation Factor A Level 1 Level 2 Mean 15 ANOVA Table Degree Freedom of Sum of square Mean sum of F-valuc Source error square error Treatment Error Total NA NA NA Recall that for single-factor ANOVA, we have the following -SSTreatments+SSp where ss,-Σ Σ(y)-T)-total sum of squares n Σ(vi-r-treatment sum of squares i- SSE _ Σ Σ(w-5)2-error sum of squares Given a dataset like the following: Treatment...
e. Set up the ANOVA table for this problem. Round all Sum of Squares to nearest...
e. Set up the ANOVA table for this problem. Round all Sum of Squares to nearest whole numbers. Round all Mean Squares to one decimal places. Round F to two decimal places. Source of Variation Sum of Squares Degrees of Freedom Mean Square F Treatments Error Total f. At the α-.05 level of significance, test whether the means for the three treatments are equal The p-value is less than.01 What is your conclusion? Select The following data are from a...
Exhibit 13-5 Part of an ANOVA table is shown below. Source of Variation Sum of Squares...
Exhibit 13-5 Part of an ANOVA table is shown below. Source of Variation Sum of Squares Degrees of Freedom F Mean Square 180 3 Between treatments Within treatments (Error) Total 480 18 Refer to Exhibit 13-5. The mean square between treatments (MSTR) is a. 300 b. 60 O c. 15 O d. 20
QUESTION 4 The following is the ANOVA data obtained from a balanced CRD: ANOVA: Source of...
QUESTION 4 The following is the ANOVA data obtained from a balanced CRD: ANOVA: Source of Variation Degree of Freedom Sum of Squares Mean Squares F-calculated 12.2 TRT ERROR 1 92.4 --- 22 45 TOTAL L Your are interested to evaluate treatments effects using the following hypothesis: Ho: M1 = M2 = ... Mt ---against--- Ha: 41 * M2 7... Mt 1. What is the number of treatments in this experiment? (place your answer in the box below) 2. Evaluate...
3. Consider the partially completed two-way ANOVA summary table. Source Sum of Squares Degrees of Freedom Mean Sum of Squares Factor B Factor A 600 200 Interaction 144 Error 384 Total 1,288 23 The number of Factor A populations being compared for this ANOVA procedure is _ A) 5 B) 7 C) 4 D) 6
21) Consider the partially completed one-way ANOVA summary table. Degrees of Mean Sum Freedom of Squares Sum of Source Squares Between 330 Within Total 1810 1 16 9 The F-test statistic for this ANOVA procedure is A) 2.33 B) 7.33 C) 5.67 D) 3.67
Mean Square (Variance) Degrees of Sum of Source Freedom Squares Consider an experiment with nine groups, with eight values in each. For the ANOVA summary table shown to the right, fill in all the missing results. Among FSTAT ? MSA 22 SSA ? c-1 ? groups Within MSW ? SSW 693 n c groups Total SST ? n-1 2 Complete the ANOVA summary table below. Degrees of Freedom Sum of Mean Square (Variance) MSA 22 Source Squares FSTAT Among groups...
a.) given the following table for a one-way ANOVA test for four
treatment groups with six subjects in each group, what would the
decision about H0 be if
?
H0 is ___ @ P ___
Source
Sum of Squares
Degrees of Freedom
Mean Squares
F Ratio
P Value
Treatment
33
Error
Total
145
a-0.05
0.0.2702 QUESTION 17 Consider the following partial ANOVA table. Source of variation df Sum of squares Mean squares Treatments Error Total 6.67 75 60 19 135 25 3.75 The numerator and denominator degrees of freedom (identified by asterisks) are, respective 1. 4 and 15 2. 3 and 16 3. 15 and 4 4. 16 and 3 5. 4 and 8
Problem 4: Complete the ANOVA table based on the following data: Replications Standard Deviation Factor A Level 1 Level 2 Mean 15 ANOVA Table Degree Freedom of Sum of square Mean sum of F-valuc Source error square error Treatment Error Total NA NA NA Recall that for single-factor ANOVA, we have the following -SSTreatments+SSp where ss,-Σ Σ(y)-T)-total sum of squares n Σ(vi-r-treatment sum of squares i- SSE _ Σ Σ(w-5)2-error sum of squares Given a dataset like the following: Treatment...
e. Set up the ANOVA table for this problem. Round all Sum of Squares to nearest whole numbers. Round all Mean Squares to one decimal places. Round F to two decimal places. Source of Variation Sum of Squares Degrees of Freedom Mean Square F Treatments Error Total f. At the α-.05 level of significance, test whether the means for the three treatments are equal The p-value is less than.01 What is your conclusion? Select The following data are from a...
Exhibit 13-5 Part of an ANOVA table is shown below. Source of Variation Sum of Squares Degrees of Freedom F Mean Square 180 3 Between treatments Within treatments (Error) Total 480 18 Refer to Exhibit 13-5. The mean square between treatments (MSTR) is a. 300 b. 60 O c. 15 O d. 20
QUESTION 4 The following is the ANOVA data obtained from a balanced CRD: ANOVA: Source of Variation Degree of Freedom Sum of Squares Mean Squares F-calculated 12.2 TRT ERROR 1 92.4 --- 22 45 TOTAL L Your are interested to evaluate treatments effects using the following hypothesis: Ho: M1 = M2 = ... Mt ---against--- Ha: 41 * M2 7... Mt 1. What is the number of treatments in this experiment? (place your answer in the box below) 2. Evaluate...
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