A)
E = Vab = 61 V
B)
A is at higher potential because there is no voltage drop of I1R1, I1 is current through R1
C)
E = Vcd = 61 V
D)
Voltage increases from b to a, so it must drop through inductor from C to d. So c is at the higher potential.
E)
I2 = 61/21 = 2.9 A
I1 = - 2.9 A
Vab = I1R1 = - 2.9 x 40 = - 116.19 V
F)
B is at higher potential
G)
Vcd = - 116.19 - 61 = - 177.19 V
D is at higher potential
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Part A Constants Just after the switch is closed, what is the magnitude of the potential...
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