Question

The roof of a two-story house makes an angle of 32" with the horizontal. A ball rolling down the roof rolls off the edge at a speed of 5.5 m/s. The distance to the ground from that point is 7.8 m. (a) How long is the ball in the air (6) How far from the base of the house does it land? et upward be the positive direction) (c) What is velocity just before and g component m y component ViewSaved We Have to Last News

Answer 1

Solution The data given in the question are as follows - Roof Ind floor 320 - x S 7.8m ty Ist floor Ball Vo=5.5m/s ground- 0 = 32', S = 7.8m, V = 5.5ms, 9= 9.8/mys? The initial Velocity (Vo) has two component in x-direction and y-direction which are V = V. Caso = 5.5 (6s 32° = 4.66 m/s Vy= Vosind = 5.5 Sin 32° = 2.91 m/s (9 When ball in the air it act in Ventical disechon it goes down using Second Kinematig equation.

Sz Vyt + 9 +2 / Puthing the given Value in equahonal) we get 7.8= 2.918 + + 1x 9.8 lt² 7.8= 5.82t+ 9.81t² 2 9.81t² + 5.82t - 15.6=0 It= 0.998 sec Ang (6) When the ball land on it ground it means it hit the ground in horizontal direction where the speed of ball is constant. the distance trovelled by the ball from the base al house is a metre. then, x= Voxt

X = 4.6680.998 x=> 4.650 m / Ano (C) the Velouty just before londing X-Component Vx = Voloso = 5.5 (0532° [vx = 4.66m/s Ang y-component Now using first Kinematic equation We get, Vy i = Vyt gt V = 2 47 + 9,81 X • 9 8 [vy = 12.700 m/s