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Exactly 0.5458 g of potassium chloride was placed in a 200 mL volumetric flask (class A)....

Exactly 0.5458 g of potassium chloride was placed in a 200 mL volumetric flask (class A). It was dissolved and diluted with distilled water up to the 200-mL mark.

Calculate:

(a) concentration of KCl in the resulting solution in g/L

(b) concentration of potassium K in this solution in g/L

(c) molarity of this solution

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Answer #1

Wt of Kd = 0·5428 g Volume of solution : 200 ml - 0.2 liter Concentration of kl = lt of kel a Vol of Solutions in dit a) 0.54

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