4)
A card's interest rate is 3.5% per quarter | |
Effective semi annual interest rate | |
Let the Principal be $100 | |
First quarter Interest will be 100*.035 -100= | 3.5 |
Second quarter will be 103.5*.035= | 3.6225 |
Semiannual Interest will | 7.1225 |
Third Quarter interest will be 107.1225*.035 | 3.749288 |
Fourth quarter interest will be (107.1225+3.749288)*.035 | 3.880513 |
Annual Interest Rate | 14.7523 |
The answer is (b)
5)
Pablo Deposits $1000 now for 10 years at 11.7% compounded semi anually | ||
The Amount formula will be A= P(1+r/100)^n | ||
If compounded semiannually A=P(1+r/200)^2n | ||
There $1000 deposited now willbecome | ||
1000*(1+11.7/200)^20 | 3117.577 | A |
A sum of $3000 deposited 4 years from now will stay invested for 6 years | ||
Using the formula above with changing n to 6 the amount will be | ||
3000(1+11.7/200)^12 | 5934.875 | B |
A sum of $1500 deposited 6 years from now will stay invested for 4 years | ||
Using the formula above with changing n to 4, the amount will be | ||
1500(1+11.7/200)^8 | 2363.84 | C |
Tte total sum available to Pablo will A+ B+C | 11416.29 |
The answer is a)
6)
A sum of $1000 every month for 5 years compounded quarterly at 40% will bed given by the formula | ||||
Pmt *( 1+ Int/period)^n*period/int/period | ||||
Here Payment is $1000 permonth or $ 3000 per quarter | 3000 | |||
Int is 40% compounded quarterly will be | 10% | |||
N will 5 years or 5X4 periods | 20 | |||
Future value will be | ||||
3000*((1.1)^20-1)/.1 | 171825 |
The answer is b
4) If the card's interest rate from problem 3 above is later changed as 3.5% per...
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