What was the purpose of adding water to the sample of vinegar used for the titration?
What was the purpose of adding water to the sample of vinegar used for the titration? The added volume was not considered in the calculations. Why was it ignored?
Homework Answers
The titration experiment is done to determine the molarity of the unknown solution. The vinegar has acetic acid in it , so water is added into it to make it dilute , though the number of moles in the acid solution remains same . This aids in the proper titration and accurate results as the determination of end point of the titration becomes easier.
This added volume due to addition of water is not considered in the calculations since we are concerned about the number of moles of acid in the solution , which does not change with addition of water.
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What was the purpose of adding water to the sample of vinegar used for the titration?
what is the purpose of adding kcn to the water sample for the titration with EDTA
what is the purpose of adding kcn to the water sample for the titration with EDTA
i need all answers Data Table 1: Titration of Vinegar with Sodium Hydroxide Vinegar Sample 1...
i
need all answers
Data Table 1: Titration of Vinegar with Sodium Hydroxide Vinegar Sample 1 Vinegar Sample 2 Vinegar Sample 3 Mass of Vinegar (6) Volume of Vinegar (ml) Density - 1.005 g/ml Initial NaOH volume in syringe (ml) Final NaOH volume in syringe (ml) Volume of NaOH delivered (mL) Volume of NaOH delivered (L) Molarity of NaOH Moles of NaOH delivered Reaction of NaOH with Acetic Acid Moles of Acetic Acid in vinegar sample Molar mass of Acetic...
6.31 M 7. Molarity of acetic acid, HC2H30in vinegar sample (show your calculations) Volume of vinegar...
6.31 M 7. Molarity of acetic acid, HC2H30in vinegar sample (show your calculations) Volume of vinegar sample = 0.003L 0.003L Vinegar contain 0.01893 moles IL 0.01893 = 6.3 IM 0.003 Vinegar contain 8. Grams of Acetic Acid, HC,H,O2 (show your calculations) 1.1368 g HC2H5O2 Grams acid = 12 *MW = 0.01893 mot x 60.052 g/ mot = 1-1368 g 31.90 % L 3 100 9. Percent (m/v) of HC,H,O, in vinegar sample (show your calculations) 3.0 mL vinegar contain 0.01893...
For vinegar titration in this experiment, would the following errors cause the % acetic acid in vinegar determined to be...
For vinegar titration in this experiment, would the
following errors cause the % acetic acid in vinegar determined to
be (A) too large, (B) too small, (C) no effect, or (D) not enough
information to answer. Assume that the mistake given is the only
mistake made in the experiment. EXPLAIN.
1.) The burst is rinsed with distilled water, but not NaOH solution
before the vinegar sample is titrated.
2.) After standardization, the NaOH solution is not stoppered and
obsorbs CO2...
What is the purpose of adding an ion pairing agent to a sample? Give example of...
What is the purpose of adding an ion pairing agent to a sample? Give example of chemical that could be added as an ion pairing agent to a water soluble vitamin. What type of molecule would serve as an ion pairing agent for a mixture of organic acids?
DATA TABLE SAMPLE 1 SAMPLE 2 SAMPLE 3 (IF NEEDED) Vinegar* Base 33.80ml Vinegar* Vinegar* Final...
DATA TABLE SAMPLE 1 SAMPLE 2 SAMPLE 3 (IF NEEDED) Vinegar* Base 33.80ml Vinegar* Vinegar* Final buret reading Base 35.45ml Base 34.30ml Initial buret reading 20.00ml 0.60ml 20.00ml 0.85ml 20.00ml 0.45ml Volume used 34.85ml 33.45ml 33.35ml *If a pipet is used to measure the volume of vinegar, record only in the space for volume used. Molarity of base (NaOH). Vinegar number 3 CALCULATIONS. In the anacor below chow calculation cetune for Samne 1 only Show answers for
What information then do you need? This is Chem 2 and not Org Chem. Titration of...
What information then do you need? This is Chem 2 and not Org
Chem.
Titration of Vinegar Lab Report 1 /25 pts) Name: Part 1: Data and Calculations mass KHC.H.O. - 4.0744 g Molecular Weight potassium hydrogen phthalate KHC.H. - [1 pt) #moles KHP = [0.5 pts) Volume of solution = 250 ml_ L10.5 pts] Concentration of KHP = Mop = _M (1 pt) Volume of KHP Solution to be titrated mL = [1 pt) #mols of KHP to be...
question 5 Laboratory Report Titration Name our Queens Run 2 Run 1 Volume of Vinegar Used...
question 5
Laboratory Report Titration Name our Queens Run 2 Run 1 Volume of Vinegar Used Concentration of NaOH 0.100 M Initial Buret reading 1.43 me Final Buret reading - 19.68 m Volume of NaOH Used 0.01sas (Final Buret reading - 1.18.25 Initial Buret reading) to Run 3 Dodac opet 0.100 M 0.100 M 119.68ml 107.69mil 36.78me. lau. Some 0.0171 0.016872 Boh 16.87 ml Calculations: 1. Calculate the number moles of base required to reach the endpoint for each run....
PART A. Titration of Vinegar Mass of empty flask Mass of flask and vinegar Mass of...
PART A. Titration of Vinegar Mass of empty flask Mass of flask and vinegar Mass of vinegar (9) Initial burette reading for NaOH (mL) Final burette reading for NaOH (mL) Volume of NaOH used (mL) Moles of NaOH used Trial 1 Trial 2 127.79 122.71 130.06 124.86 2.27 2.15 o 21.10 21.10 40.65 21.10 19.55 Moles of acetic acid that was titrated Mass of acetic acid that was titrated (9) Mass % of acetic acid in vinegar sample
Prelab Activity: Titrations Continued – Titration of Household Products A 2.40 g sample of vinegar was...
Prelab Activity: Titrations Continued – Titration of Household Products A 2.40 g sample of vinegar was added to an Erlenmeyer flask along with 100 mL of deionized water and 3 drops of phenolphthalein indicator. It took 22.15 mL of 0.0981 M NaOH (aq) to reach the faint pink endpoint. The following balanced chemical equation represents the chemistry of the titration: NaOH (aq) + CH3COOH (aq) à CH3COO–Na+ (aq) + H2O (l) Calculate the mass % of acetic acid (CH3COOH) in...
i
need all answers
Data Table 1: Titration of Vinegar with Sodium Hydroxide Vinegar Sample 1 Vinegar Sample 2 Vinegar Sample 3 Mass of Vinegar (6) Volume of Vinegar (ml) Density - 1.005 g/ml Initial NaOH volume in syringe (ml) Final NaOH volume in syringe (ml) Volume of NaOH delivered (mL) Volume of NaOH delivered (L) Molarity of NaOH Moles of NaOH delivered Reaction of NaOH with Acetic Acid Moles of Acetic Acid in vinegar sample Molar mass of Acetic...
6.31 M 7. Molarity of acetic acid, HC2H30in vinegar sample (show your calculations) Volume of vinegar sample = 0.003L 0.003L Vinegar contain 0.01893 moles IL 0.01893 = 6.3 IM 0.003 Vinegar contain 8. Grams of Acetic Acid, HC,H,O2 (show your calculations) 1.1368 g HC2H5O2 Grams acid = 12 *MW = 0.01893 mot x 60.052 g/ mot = 1-1368 g 31.90 % L 3 100 9. Percent (m/v) of HC,H,O, in vinegar sample (show your calculations) 3.0 mL vinegar contain 0.01893...
For vinegar titration in this experiment, would the
following errors cause the % acetic acid in vinegar determined to
be (A) too large, (B) too small, (C) no effect, or (D) not enough
information to answer. Assume that the mistake given is the only
mistake made in the experiment. EXPLAIN.
1.) The burst is rinsed with distilled water, but not NaOH solution
before the vinegar sample is titrated.
2.) After standardization, the NaOH solution is not stoppered and
obsorbs CO2...
DATA TABLE SAMPLE 1 SAMPLE 2 SAMPLE 3 (IF NEEDED) Vinegar* Base 33.80ml Vinegar* Vinegar* Final buret reading Base 35.45ml Base 34.30ml Initial buret reading 20.00ml 0.60ml 20.00ml 0.85ml 20.00ml 0.45ml Volume used 34.85ml 33.45ml 33.35ml *If a pipet is used to measure the volume of vinegar, record only in the space for volume used. Molarity of base (NaOH). Vinegar number 3 CALCULATIONS. In the anacor below chow calculation cetune for Samne 1 only Show answers for
What information then do you need? This is Chem 2 and not Org
Chem.
Titration of Vinegar Lab Report 1 /25 pts) Name: Part 1: Data and Calculations mass KHC.H.O. - 4.0744 g Molecular Weight potassium hydrogen phthalate KHC.H. - [1 pt) #moles KHP = [0.5 pts) Volume of solution = 250 ml_ L10.5 pts] Concentration of KHP = Mop = _M (1 pt) Volume of KHP Solution to be titrated mL = [1 pt) #mols of KHP to be...
question 5
Laboratory Report Titration Name our Queens Run 2 Run 1 Volume of Vinegar Used Concentration of NaOH 0.100 M Initial Buret reading 1.43 me Final Buret reading - 19.68 m Volume of NaOH Used 0.01sas (Final Buret reading - 1.18.25 Initial Buret reading) to Run 3 Dodac opet 0.100 M 0.100 M 119.68ml 107.69mil 36.78me. lau. Some 0.0171 0.016872 Boh 16.87 ml Calculations: 1. Calculate the number moles of base required to reach the endpoint for each run....
PART A. Titration of Vinegar Mass of empty flask Mass of flask and vinegar Mass of vinegar (9) Initial burette reading for NaOH (mL) Final burette reading for NaOH (mL) Volume of NaOH used (mL) Moles of NaOH used Trial 1 Trial 2 127.79 122.71 130.06 124.86 2.27 2.15 o 21.10 21.10 40.65 21.10 19.55 Moles of acetic acid that was titrated Mass of acetic acid that was titrated (9) Mass % of acetic acid in vinegar sample
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