Question

A B C D E F 8' 8' 8' 8' 8' civil engineering

Draw influence lines (show the values and locations for all key points) for the following: Karagi programoginta a) Influence Line for Vertical (upwards) Reaction at F, Fy b) Influence Line for Vertical Reaction at B, BY c) Influence Line for Positive Internal Shear Force just to the right of D, Veight d) Influence Line for Positive Internal Bending Moment at B, M, e) Maximum value of By with a distributed dead load of 1 k/ft, distributed live load of 4 k/ft that may be placed anywhere on the span, and a single concentrated live load of 5 kips that can also be placed in any location. Clearly show the locations of the loadings that cause the maximum effect in the space below. I II III Maximum value of By =

Answer 1

Salution Given beam- A_ B C D - - - - - 1 I.L.D for f - - - - - I.L.D for By E - - - - I.LD for Vp-right. 3 i esch 0.7 I Tu

( Expeanations @ Influence lines for ventical (Upwards) Reaction at F. Fy from muller Breslaw's Principal: without removing the Support at B and remove the support at F and give Unit displacement, the deflected Shape of beam is itself I L.D for Reaction at F, Fy (6) Influence line for vertical reaction at B, By 1 from muller Breslaw's Principal, without Removing the support at D and F give unit displacement at B after removing the support at B the deflected Shape of beam is itself I.L.D for By, 0 Influence line for positive internal shear force Just to the right of D, V-right! from muller, To draw I L. D for Shear force at right of Do cut the beam at D and lift the beam such that Oo= a = then the corresponding deflected shape of the beam itself is It.D for sf V-right. (d) Influence line for positive internal Bending moment at B; mo without removing the support cut B, D & F assume an Ingaginary chinge at B & give unit rotation, then deflected Shape I of the beam itself is the I.L.O for Bim at B, Mg.

Maximum value of by with a distributed dead load Ik/ft, Distributed live load of 4K/Ht that may be placed anywhere on the span, and a single concentrated line load of skips that can also be placed in any location I.L.D for By : 15 kipsi DELIKA na 2 L2= 4x/ht! 8' B 8'' gro 81 € 8' I.L.D for By For maximum value of By Concentrated load at put the LL on point A. only span AC and then maximum value of By = (4+1)*1*2*16 + 5*2 = 80 + 10 - gokips. A o peeps Answer