Question

2. Light of wavelength 440 nm passes through two slits of equal width, yielding an interference pattern whose graph of intensity versus angular position 0 is shown in the figure (a) Calculate the width A of each slit. Explain _ie 4.0 deg) your method -4.0 (b) Calculate the distance between the two slits. Explain your reasoning. (c) Suppose the width of each of the slits is doubled, but the separation of the two slits does not change. Sketch the new intensity pattern on the graph below Explain your re 4.0 e(deg) -4.0 (d) Suppose the width of the slits is not changed from its original value, but the separa of the two slits is reduced by half Sketch the new intensity pattern on the graph below. Explain your reasoning 4.0 (deg) -4.0

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Answer #1

from the given graph angular fringewidth 360 angular fringewi dth 2? ct wi dth of each slit, 22 2(440nm) 0,01?rad a= 5.0×104nm a-50x10-6m : 50?m fringewidth due to double slit di stance between the slits is a (440nm) 0,01?rad a= 2.5×104nm a = 25x10-6m = 501m ct 42a2 intensity doesnot changes. but fringe width will become half

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