Question

20 N 36 mm 25 mm 25 mm 120 N -65 mm- Problem 6.106 The woman exerts 20-N forces on the handles of the shears. Determine the magnitude of the forces exerted on the branch at A.
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Answer #1

Considering vertical component,

Dy + 20 - Ey - 20 = 0

Dy = Ey

Now considering horizontal component,

Dx = Ex

Taking moment about point C,

Dy(25) - (20 (65 + 25)) - (Dx (x)) - (Ey x 25) + (20 (65 + 25)) - (Ex (x)) = 0

Substituting Dy for Ey and Dx in place of Ex

So,

Dx = 0

Again taking moment about point C,

Dy x 25 - (20 x 90) - (Dx (x)) = 0

Dy = 72 N

Taking moment about point B,

(Ay x 36) - (72 x 50) = 0

Ay = 100 N

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