Question

*18% 8:30 Working with Phasors and Using Complex Polar Notation in MATLAB By default, MATLAB accepts complex numbers only in rectangular form. Use i or j to represent the imaginary number. Type the following expressions >> in Matlab and print out the results ans = >> 5+41 ans = A number in polar form, such as (2245), can be entered using complex exponential notation. The angle must be converted to radians when entering numbers in complex exponential form: >> X = 2*exp(j*45*pi/180) ans - It is convenient to define radian/degree conversion functions as follows: >> d2r - (x) (x*pi/180); >r20 - (x) (x*180/pi); The previous expression can now be entered as: >> X = 2*exp()*d2r (45)) ans = The abs and angle functions can be used to find the polar form components of a complex number: >> (abs(x) r20 (angle(x))] ans = Here are some additional examples: >> Z = (7+8i+20+exp (j+d2r (-30) ) ) / (5*exp(j*d2r (45)) ) > [abs(z) r2(angle(z))] ans = >> volts = [10*exp(j*d2r (45)); 20*exp(j*d2r(-30)); 100) ans = PRINT OUT THE MATLAB RESULTS AND INCLUDE IN THE HOMEWORKI WRITE-UP

Answer 1

Matlab simulated codes and its results are uploaded here. One can simulate these codes either in command window or Live script.

>> 5+41 ans 5.0000 + 4.0000

>> x=2*exp(10*45*pi/180) 1.4142 + 1.4142i >> x=2*exp(1j*d2r (45)) radian_angle = 0.7854 * 1.4142 + 1.4142i

>> [abs(x) r2d (angle (x))] degree angle = ans = 2 45 >> z=(7+8j+20*exp(1j*d2r(-30) ) )/(5*exp(1j*d2r (45))) radian_angle = -0.5236 radian_angle = 0.7854 3.1566 - 3.7223i

>> [abs (z) r2(angle (z))] degree angle = -49.7011 ans = 4.8805 -49.7011 >> volts=[10*exp(lj*d2r (45));20*exp(1j*d2r (-30));100] radian_angle = 0.7854 radian_angle = -0.5236 volts = 1.0e+02 * 0.0707 + 0.0707i 0.1732 - 0.1000i 1.0000 + 0.0000i fx >> |

Defined functions for conversion of angle is as following. We have to create these functions in Mscript.

d2r. mx r2d. mx + function (radian_angle]=d2r (9) 2 - -radian_angle=q* (pi/180)

Id2r. mx r2d. mx + i function [degree_angle] = r2(x) degree angle=x*180/pi