Question

The Nielsen Company is a global information and media company and one of the leading suppliers of media infomatian. In their state-of-the-media report, they announced that U.S. cell phone subscribers average 5.4 hours per month watching videos on their phones. We decide to construct a 95% confidence interval for the average time (hours per month) spent watching videos on cell phones among U.S. College students. we draw the following SRS of Size 8 from this population. (Round your answers to two decimal places.) 11.9 2.7 3.0 6.2 4.6 9.8 11.2 7.7 The sample mean is 11.9 2.7 +7.7 and the standard deviation is the tollowing. The degrees of freedom n 1- The standard error is SE+F From Table D we find t* = 2.365. The 95% confidence interval is the following. (Round your answers to two decimal places.) +2.365 2.365 wc arc 95% confident that armong u.s. college students, the average time spent watching videos on 려 cell phone is betwecn and hours per month.

Answer 1

Х-Х 22.68141 19.69141 17.11891 0.878906 6.438906 7.088906 16.50391 0.316406 90.71875 11.9 27 6.2 4.6 9.8 11.2 7.7 57.1 4

2x 57.1 Mean= 7.1375 8 Σ(x-が-90.71875-12.95982 Variance n-1 8-1 Standard deviation-VVariance-V12.95982-3.599975-3.6 Standard error SEr 1.2728 df n-1-8-1-7 C 0.95 a- 1-0.95-0.05 t-t2d to.025,7-2.365 (using t value table at df12) 95% confidence interval x t * s 3.6 7.1375 +2.3655 V8 -7.13752.365 1.2728 =7.1375± 3.0102 4.1273, 10.1477) We are 95% confidence that among U. S college students the average time watching videos on a cell phone is between 4.1273 and 10.1477 hours per month Using excel the answer is =71375± (TINV (0.05, 7)*3.6/sart (8)) 4.12782468 , 10.1471753)