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Problem 7.11 The switch in the circuit shown in (Figure 1) has been in position 1 for a long time. At t = 0, the switch moves
Part A Find the value of R so that 34% of the initial energy stored in the 30 mH inductor is dissipated in R in 24js. Express
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Į at to the circuit is 3A ukr} w tiro qe iro] = 3A +=of the circuit is at 3A Lek SomH Z D3A energy w= į Lico Intial → W = { xFor to the {lt) is given by int) = iz (m) + (com) – 14 (a) e ty -3 30X10 0-0 Where L Cot] =3A (69) = 01 ſi source free] Y = L0.66 X W[24 us] = 0.66 $0.135 TW (24.46] = 0.0891 Jones Now = W (24.957 L 12 (247) x30x 70% [24 moi * = 0.0891 0.0891x2 ů (24

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