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A uniform film of TiO2, 1036 nm thick and having index of refraction 2.62, is spread...

A uniform film of TiO2, 1036 nm thick and having index of refraction 2.62, is spread uniformly over the surface of crown glass of refractive index 1.52. Light of wavelength 600 nm falls at normal incidence onto the film from air. You want to increase the thickness of this film so that the reflected light cancels.

What is the minimum thickness of TiO2 that you must add so the reflected light cancels as desired?

After you make the adjustment in part (a), what is the path difference between the light reflected off the top of the film and the light that cancels it after traveling through the film? Express your answer in nanometers.

Express your answer in wavelengths of the light in the TiO2 film.

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Answer #1

2T T- I14.so 3 & (m) 2n 2P2.62 Tmust be lo36 n m greater than 70 П45.04 add l09.01 1 AT: Path diffenens 2T= 2 x 4S.04 2290. 0

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