Question

The single-phase full converter as shown in Figure 8-1 has an RL load having L = 5 mH, R-0.8 Ω, and E -0 V. The input voltage is Vs = 120 V at(rms) 60 Hz. The delay angle or-α-300 Calculate the performance parameters. Assume ideal thyristor switches. the rms thyristor current IR Figure 8-1 Single-Phase Full Converter T1 T4 太T2 0

Answer 1

$V_m=\sqrt{2}V_s=120\sqrt{2}\;V$

$\alpha =30^o$

$R =0.8\;\Omega$

The average output current is given by

$I_{dc}=\frac{2V_m\cos \alpha }{\pi R}$

$I_{dc}=\frac{2\times 120\sqrt{2}\times\cos 30^o }{\pi \times0.8}$

$I_{dc}=116.95\;A$

Therefore RMS thyristor current is given by

$I_{T_{rms}}=\frac{I_{dc}}{\sqrt{2}}$

$I_{T_{rms}}=\frac{116.95}{\sqrt{2}}$

${\color{Red} I_{T_{rms}}=82.696 \;A}$