Question

Mendel crossed green and yellow peas and all of the hybrids were yellow. When the hybrids self-fertilized to get another generation about what proportion of their progeny were yellow? a. 1/4 of them b. about half of them c. all of them d. none of them 6. 3/4 of them QUESTION 2 You find a patch of peas in which 3/4 of the peas are yellow and 1/4 of the peas were green. Assuming that all of the peas were the product of a single set of parents, what can you inter about the parents? both parents were green and both were heterozygous b. both parents were yellow and both were heterozygous one parent was yellow, one was green and both were heterozygous one parent was yellow, one was green and both were homorygous one parent was yellow, one was green and one parent was heterozygous QUESTION 3 F3: When you examined the F3 progeny of F2 peas, which of the following events did you NOT observe? Yellow P2 peas with mixed yellow and green F3 progeny b. Green F2 peas with only green F3 progeny . Green F2 peas with minced yellow and green F3 progeny d. Yellow F2 peas with only yellow F3 progeny

Answer 1

Answer: E is the answer.

Green and yellow plants gives yellow in F1. This suggests that yellow trait is dominant over green trait.

Let Y allele encodes yellow and it is dominant over y allele. y alleme in homozygous recessive conditions produce green color.

Parents: Yellow (YY) × green (yy)

F1: Yy yellow

When F1 are self crossed;

Parents: Yy × Yy

Punent square:

Gametes	Y	y
Y	YY (yellow)	Yy ( yellow)
y	Yy ( yellow)	yy ( green)

That's why 3/4 are yellow. And 1/4 are green.

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Answer 2) Answer is b is the right answer.

As discussed above that Yell plant which are heterozygous in nature give 3 (yellow) : 1( green) phenotypic ratio.

Answer 3)

c is the answer.

Green (yy) × Yellow (YY/ Yy)

Here the Y allele is present in yellow plant. When this allele bearing gamete fuses with y allele, then yellow phenotype is also found in progeny.

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