A capacitor consists of two short sections of parallel wires in air. The voltage on one...
A capacitor consists of two short sections of parallel wires in air. The voltage on one wire is 60 V and on the other is -60 V. The two wires carry equal and opposite charge with the magnitude of 476 pC. Find the capacitance of the capacitor in pF
Homework Answers
capacitance is C = Q/V
Q is the charge on the plates = 476 pC
V is the voltage across plates = 60 V
then Capacitance is C = (476*10^-12)/60 = 7.93*10^-12 F = 7.93
pF
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