Homework Answers
a)
C= q/ΔV
C = (0.0153*10^-6C)/(200) = 0.765*10^-10F
b)
C = ϵo A/ d
A = Cb / ϵo
A = (0.765*10^-10)*(2.15*10^-3)/(8.854*10^-12C/Nm^2) = 0.0185m
c)
EST = 1/2 QΔV
EST = 1/2 (0.0153*10^-6)(200) = 1.53*10^-6j
d)
3e6 v/m x 0.0215 m = 64500 volts
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