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A parallel plate capacitor is made of plates of area 0.05 m? each. The plates are...
The charge on the 4.00 cm2 area plates of an air-filled parallel plate capacitor is such...
The charge on the 4.00 cm2 area plates of an air-filled parallel plate capacitor is such that the electric field is at the breakdown value. By what factor will the maximum charge on the plates increase when polystyrene is inserted between the plates? (The dielectric strength of air is 3.00 × 106 V/m and that of polystyrene is 2.40 x 107 V/m. The dielectric constant of polystyrene is 2.56. Supporting Materials Physical Constants Additional Materials Tutorial
An air capacitor is made from two flat parallel plates 2.15 mm apart. The magnitude of...
An air capacitor is made from two flat parallel plates 2.15 mm apart. The magnitude of charge on each plate is 0.0153 mu C when the potential difference is 200 V. (a) What is the capacitance? PF (b) What is the area of each plate? m^2 (c) What maximum voltage can be applied without dielectric breakdown? (Dielectric breakdown for air occurs at an electric-field strength of 3.00 times 10^6 V/m.) V (d) When the charge is 0.0153 mu C, what...
A parallel plate capacitor has square plates with sides of length 11 cm. The distance between...
A parallel plate capacitor has square plates with sides of length 11 cm. The distance between the plates is 2 mm. The plates are charged up to 20volts. Part A What is the electric field between the plates? Express your answer using three significant figures. Electric field = N/C Part B What is the amount of charge on each plate? charge = C Part C What is the capacitance? Capacitance = μF Part D What is the energy stored by...
The plates of an air-filled parallel-plate capacitor with a plate area of 16.5 cm2 and a...
The plates of an air-filled parallel-plate capacitor with a plate area of 16.5 cm2 and a separation of 8.80 mm are charged to a 130-V potential difference. After the plates are disconnected from the source, a porcelain dielectric with κ = 6.5 is inserted between the plates of the capacitor. (a) What is the charge on the capacitor before and after the dielectric is inserted? Qi = ___C Qf = ____C (b) What is the capacitance of the capacitor after...
(a) How much charge can be placed on a capacitor with air between the plates before...
(a) How much charge can be placed on a capacitor with air between the plates before it breaks down if the area of each plate is 2.00 cm2? (Assume air has a dielectric strength of 3.00 ✕ 106 V/m and dielectric constant of 1.00.) nC (b) Find the maximum charge if polystyrene is used between the plates instead of air. (Assume polystyrene has a dielectric strength of 24.0 ✕ 106 V/m and dielectric constant of 2.56.) nC
An uncharged parallel-plate capacitor with only air between the plates has C◦ = 0.600 mF. It...
An uncharged parallel-plate capacitor with only air between the plates has C◦ = 0.600 mF. It is connected to an EMF source with E = 6.00 V. a) How much charge Q◦ accumulates on the cap, and how much energy is stored, U◦? b) The capacitor is discharged back to zero, then filled with a dielectric material that brings its capacitance up to C1 = 1.950 mF. What is the value of κ1 for the dielectric material? When connected to...
1. Two parallel plates, each of area 5.17 cm2, are separated by 4.90 mm. The space...
1. Two parallel plates, each of area 5.17 cm2, are separated by 4.90 mm. The space between the plates is filled with air. A voltage of 4.75 V is applied between the plates. Calculate the magnitude of the electric field between the plates. 2. Calculate the amount of the electric charge stored on each plate. 3. Now distilled water is placed between the plates and the capacitor is charged up again to the same voltage as before. Calculate the magnitude...
An air-filled capacitor is made from two flat parallel plates 1.4 mm apart. The inside area...
An air-filled capacitor is made from two flat parallel plates 1.4 mm apart. The inside area of each plate is 8.8 cm2. a) What is the capacitance of this set of plates (in pF) b) If the region between the plates is filled with a material whose dielectric constant is 6.6, what is the new capacitance (in pF)? 2) A parallel-plate capacitor with only air between its plates is charged by connecting the capacitor to a battery. The capacitor is...
Two parallel plates, each of area 3.37 cm2, are separated by 4.80 mm. The space between...
Two parallel plates, each of area 3.37 cm2, are separated by 4.80 mm. The space between the plates is filled with air. A voltage of 6.25 V is applied between the plates. Calculate the magnitude of the electric field between the plates. Tries 0/20 Calculate the amount of the electric charge stored on each plate. Tries 0/20 Now distilled water is placed between the plates and the capacitor is charged up again to the same voltage as before. Calculate the...
The two plates of a parallel-plate capacitor each have an area of 2.09 × 10-2 m2....
The two plates of a parallel-plate capacitor each have an area of 2.09 × 10-2 m2. The separation between the plates is 0.124 mm and the space between the plates is filled with a material with a dielectric constant of 4.45. (a) What is the capacitance of this capacitor? (b) If the plates are connected to the terminals of a battery so that the magnitude of the potential difference between the plates is 8.13 V, what is the magnitude of...
The charge on the 4.00 cm2 area plates of an air-filled parallel plate capacitor is such that the electric field is at the breakdown value. By what factor will the maximum charge on the plates increase when polystyrene is inserted between the plates? (The dielectric strength of air is 3.00 × 106 V/m and that of polystyrene is 2.40 x 107 V/m. The dielectric constant of polystyrene is 2.56. Supporting Materials Physical Constants Additional Materials Tutorial
An air capacitor is made from two flat parallel plates 2.15 mm apart. The magnitude of charge on each plate is 0.0153 mu C when the potential difference is 200 V. (a) What is the capacitance? PF (b) What is the area of each plate? m^2 (c) What maximum voltage can be applied without dielectric breakdown? (Dielectric breakdown for air occurs at an electric-field strength of 3.00 times 10^6 V/m.) V (d) When the charge is 0.0153 mu C, what...
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