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Select a suitable wide flange section to support the beam loads shown in the figure below....
2 - Select the lightest-weight wide-flange beam from Appendix B that will safely support the loading....
2 - Select the lightest-weight wide-flange beam from Appendix B that will safely support the loading. The allowable bending stress is sallow - 22 ksi and the allowable shear stress is tallow 12 ksi. 5 kip 18 kip ft 6 ft 12 ft
Select the lightest W shape for the loading below. All loads are dead loads and the...
Select the lightest W shape for the loading below. All loads are dead loads and the 2 k/ft includes th beam weight. The steel is A992, the compression flange is supported at the ends and at the concentrated load and C 1.0. The maximum service load deflection cannot exceed 1/1000 of the span. Design for moment and check shear and deflection. Identify what zone the beam is in and check that it does not exceed zone 1 maximum strength. 13...
D . Select the lightest-weight steel wide-flange overhanging beam from Appendix B that will safely support...
D . Select the lightest-weight steel wide-flange overhanging beam from Appendix B that will safely support the loading. Assume the support at A is a pin and the support Jo now = 12 ks: at B is a roller. The allowable bending stress is allow = (see email data) Zaves IU KS and the allowable shear stress is allow --- 14 ksi. P=11 hip 8t 44 y. Selected beam section is: W X P (see email data for value of...
Select the lightest adequate W-section with a nominal depth of 14 in or less, for a...
Select the lightest adequate W-section with a nominal depth of 14 in or less, for a 34ft. beam with a total uniformly distributed load of 1000 lb/ft. Select the beam based only on bending stress then check to see if deflection is O.K. LL Allowable deflection = L/360 TL Allowable deflection = L/240 Fb = 2/3 FY Fy = 50,000 lb/in2 LL is 70% of total load. No figure given. Find M max = Sr = Selection = delta LL...
Mmax, Sr, Selection, delta LL allow, delta LL max, Deflection ok? Select the lightest adequate W-section...
Mmax, Sr, Selection, delta LL allow, delta LL max, Deflection
ok?
Select the lightest adequate W-section with a nominal depth of 14 in or less, for a 34ft. beam with a total uniformly distributed load of 1000 lb/ft. Select the beam based only on bending stress then check to see if deflection is O.K. LL Allowable deflection = L/360 TL Allowable deflection = L/240 Fb = 2/3 FY Fy = 50,000 lb/in2 LL is 70% of total load
Problem 1 (100 pts) Select the lightest W24 beam section with Fy = 50 ksi using...
Problem 1 (100 pts) Select the lightest W24 beam section with Fy = 50 ksi using LRFD for the following span and loading. The unbraced length of the compression flange is 30 ft (Lb = 30'). Consider Cb > 1. The given dead load does not include beam weight. Verify that the selected beam has adequate shear strength. Maximum allowable deflection due to live load is L720. Maximum allowable deflection due to total load is L/360. WD = 1.2 k/ft...
A flanged wooden shape is used to support the loads shown on the beam. The dimensions...
A flanged wooden shape is used to support the loads shown on the beam. The dimensions of the shape are shown in the second figure. Assume LAB = 7 ft, Lec = 4 ft, Lcd = 4 ft, LDE = 2 ft, Pc = 1730 lb, PE = 2320 lb, WAB = 710 lb/ft, b = 8 in., b2 = 2 in., b3 = 5 in., da = 2 in., d2 = 7 in., dz = 2 in. Consider the...
Select the lightest adequate W-section with a nominal depth of 14 in or less, for a...
Select the lightest adequate W-section with a nominal depth of 14 in or less, for a 34ft. beam with a total uniformly distributed load of 1000 lb/ft. Select the beam based only on bending stress then check to see if deflection is O.K. LL Allowable deflection = L/360 TL Allowable deflection = L/240 Fb = 2/3 FY Fy = 50,000 lb/in2 LL is 70% of total load M max = Select one: a. 4.25 k-ft b. 144.5 k-ft c. 101.1...
A flanged wooden shape is used to support the loads shown on the beam. The dimensions...
A flanged wooden shape is used to support the loads shown on the beam. The dimensions of the shape are shown in the second figure. Assume LAB = 6 ft, LBC = 2 ft, LCD = 2 ft, LDE = 4 ft, PC = 1700 lb, PE = 1750 lb, wAB = 610 lb/ft, b1 = 7 in., b2 = 2 in., b3 = 3 in., d1 = 2 in., d2 = 11 in., d3 = 2 in. Consider the...
A flanged wooden shape is used to support the loads shown on the beam. The dimensions...
A flanged wooden shape is used to support the loads shown on the beam. The dimensions of the shape are shown in the second figure. Assume LAB = 5 ft. LBC = 2 ft, LCD= 3 ft, LDE = 4 ft, Pc = 2060 lb, Pe= 1990 lb, WAB = 750 lb/ft, b1 = 10 in., b2 = 2 in., b3 = 7 in., dų = 2 in., d2 = 8 in., d3= 2 in. Consider the entire 14-ft length...
2 - Select the lightest-weight wide-flange beam from Appendix B that will safely support the loading. The allowable bending stress is sallow - 22 ksi and the allowable shear stress is tallow 12 ksi. 5 kip 18 kip ft 6 ft 12 ft
Select the lightest W shape for the loading below. All loads are dead loads and the 2 k/ft includes th beam weight. The steel is A992, the compression flange is supported at the ends and at the concentrated load and C 1.0. The maximum service load deflection cannot exceed 1/1000 of the span. Design for moment and check shear and deflection. Identify what zone the beam is in and check that it does not exceed zone 1 maximum strength. 13...
D . Select the lightest-weight steel wide-flange overhanging beam from Appendix B that will safely support the loading. Assume the support at A is a pin and the support Jo now = 12 ks: at B is a roller. The allowable bending stress is allow = (see email data) Zaves IU KS and the allowable shear stress is allow --- 14 ksi. P=11 hip 8t 44 y. Selected beam section is: W X P (see email data for value of...
Mmax, Sr, Selection, delta LL allow, delta LL max, Deflection
ok?
Select the lightest adequate W-section with a nominal depth of 14 in or less, for a 34ft. beam with a total uniformly distributed load of 1000 lb/ft. Select the beam based only on bending stress then check to see if deflection is O.K. LL Allowable deflection = L/360 TL Allowable deflection = L/240 Fb = 2/3 FY Fy = 50,000 lb/in2 LL is 70% of total load
Problem 1 (100 pts) Select the lightest W24 beam section with Fy = 50 ksi using LRFD for the following span and loading. The unbraced length of the compression flange is 30 ft (Lb = 30'). Consider Cb > 1. The given dead load does not include beam weight. Verify that the selected beam has adequate shear strength. Maximum allowable deflection due to live load is L720. Maximum allowable deflection due to total load is L/360. WD = 1.2 k/ft...
A flanged wooden shape is used to support the loads shown on the beam. The dimensions of the shape are shown in the second figure. Assume LAB = 7 ft, Lec = 4 ft, Lcd = 4 ft, LDE = 2 ft, Pc = 1730 lb, PE = 2320 lb, WAB = 710 lb/ft, b = 8 in., b2 = 2 in., b3 = 5 in., da = 2 in., d2 = 7 in., dz = 2 in. Consider the...
A flanged wooden shape is used to support the loads shown on the beam. The dimensions of the shape are shown in the second figure. Assume LAB = 5 ft. LBC = 2 ft, LCD= 3 ft, LDE = 4 ft, Pc = 2060 lb, Pe= 1990 lb, WAB = 750 lb/ft, b1 = 10 in., b2 = 2 in., b3 = 7 in., dų = 2 in., d2 = 8 in., d3= 2 in. Consider the entire 14-ft length...
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