Question

You must show all calculations in order to get the full score. They must be handmade. Consider a cross between two black gimos that are heterozygous (Bb). to. How many possible combinations will produce 13 black children and 4 white children? b. What is the probability that 13 blacks and 4 whites appear in that order

Consider a cross between two black gimos that are heterozygous (Bb).

to. How many possible combinations will produce 13 black children and 4 white children?

b. What is the probability that 13 blacks and 4 whites appear in that order

Answer 1

Answer :

Given that :

no.of blacks = 13

no.of whites = 4

Total no.of children = 13 + 4 = 17

Hetrozygous = Bb

Now do cross between two blackdog

Bb * Bb

	B	b
B	BB	Bb
b	Bb	bb

a)We need to find the possible combinations for black ad white children :

i.e $17C _{13} * 17C_{4}$

= 2380 * 2380

= 5664400

Therefore,

No.of possibilities for 13 black and 4 white appear in order = 5664400

b)Here the probability that 13 black and 4 white appear in order is as follows :

P = 2! * 31 * 4! * 5664400

= 2 * 6 * 24 * 5664400

= 1631347200