Question

Explain steps and include formula if used

4. A charged plastic rod of length 2.44 m is formed into an arc that covers a subtended angle of 70 The total charge on the rod us 4uC. Calculate the electric field at the center of the arc. (You will need to find " and recall that 1-0.017444 radians and s r, where theta is in radians.)

Answer 1

Length of plastic rod s = 2.44 m therefore s = r theta & theta = 70 degree = 70 pi/180 radians therefore r = 2.44/(70 pi/180) r = 1.99717 m charge on the rod is Q = 4 micro c linear charge density of rod lambda = Q/s = 4/2.44 Now, the electric field at the centre of the are of angle �theta� is given by E = k d/r (2 sin theta) Here theta = 70 degree r = 1.99716717 m, k = 9 times 10^9 N m^2/c^2 so E = (9 times 10^9) { (4/2.44) times 10^-6} times 2 sin 70/1.99716717 E = 13.884 times 10^3 N/c E = 13.884 K N/c