Question

An observational study of Alzheimer's disease (AD) obtained data from 13 AD patients exhibiting moderate dementia and selected a group of 8 control individuals without AD. AD is a progressive neurodegenerative disease of the elderly and advancing age is known to be a primary risk factor in AD diagnosis. Therefore, it was crucial for the study's credibility to examine whether the ages in the AD group might be significantly different than in the control group. The ages of the subjects in years are summarized in the Minitab Output below. ----------------------------------------------------------------------------------------------------------------------- Descriptive Statistics: Alzheimers, Control Variable N N* Mean SE Mean StDev Minimum Q1 Median Q3 Maximum Alzheimers 13 0 78.81 1.86 6.72 77.00 79.25 87.00 92.25 93.00 Control 8 0 65.44 4.53 12.82 54.00 56.00 65.00 82.00 89.00 ----------------------------------------------------------------------------------------------------------------------- We want to test if the average age in the Alzheimer's group is significantly different than the control group. (a) What is the null hypothesis? (b) Find the value of the test statistic. (c) Find the 5% critical value. (d) What is the conclusion of the hypothesis test? (A) H0 : μ1 ≥ μ2 (B) H0 : μ1 > μ2 (C) H0 : μ1 ≠ μ2 (D) H0 : μ1 = μ2 (E) H0 : μ1 < μ2 (F) H0 : μ1 ≤ μ2 (A) Reject H0 since the p-value is equal to 0.0064 which is less than .05. (B) Do not reject H0 since the p-value is equal to 0.0064 which is less than .05. (C) Reject H0 since the absolue value of the answer in (b) is greater than the answer in (c). (D) Do not reject H0 since the p-value is equal to 0.0032 which is less than .05. (E) Do not reject H0 since the absolue value of the answer in (b) is less than the answer in (c). (F) Do not reject H0 since the absolue value of the answer in (b) is greater than the answer in (c). (G) Reject H0 since the absolue value of the answer in (b) is less than the answer in (c). (H) Reject H0 since the p-value is equal to 0.0032 which is less than .05.

Answer 1

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