Question

Part B Rank each pendulum on the basis of the maximum kinetic energy it attains after release Rank from largest to smallest To rank items as equivalent, overlap them h=60cm m=2kg h 60 cm h-30 cm m=2kg h=45 cm m - 3 kg h 30 cm h = 15 cm m=8kg m= largest smallest The correct ranking cannot be determined reset help

Answer 1

Part B: as 1,2,3,4,5, and 6 respectively Let label the six pendulums from left to right Apply law of conservation of energy The potential energy at extreme point is equal to the maximum kinetic energy attained by the pendulum PE KE 1 mgh my 1 -mv = mgh 2gh For pendulum 1, the maximum kinetic energy is, 1 KE 2 1 m(2gh) 2 1 (2 kg 2(9.8 ms(0.6 m -11.76 J For pendulum 2, the maximum kinetic energy is, 1 mv KE2 (2gh,) m (1 kg) 2(9.8 m/s) 0.6 m) -5.88 J For pendulum 3, the maximum kinetic energy is, 1 KE -m(2gh,) 1 (8 kg) 2(9.8 m/s2 0.15 m) -11.76 J

For pendulum 4, the maximum kinetic energy is, 1 mv2 KE4 4 2 1 -m(2 gh,) 2 2 kg2(9.8 m/s) (0.3 m)] -5.88 J For pendulum 5, the maximum kinetic energy is, 1 mv 5 2 KE 1 (2gh) (4kg) 2(9.8 m/s)(0.3 m) -11.76 J For pendulum 6, the maximum kinetic energy is 1 KE -mv 6 2 1 (2gh) 2 m =_ (3 kg 2(9.8 m/s -13.23 J Therefore, the rank of pendulums from largest to smallest is 6>1 =3=5>2=4

Part C For pendulum 1, the maximum speed is, /2gh = 2(9.8 m/s (0.6 m) = -3.43 m/s For pendulum 2, the maximum speed is, 22gh j2(9.8 m/s2)(0.45 m) = = -2.97 m/s For pendulum 3, the maximum speed is 2gh 2(9.8 m/s2(0.3 m -2.42 m/s For pendulum 4, the maximum speed is ,2gh (9.8 m/s) (0.3 m) = = -2.42 m/s For pendulum 5, the maximum speed is, 2gh 2(9.8 m/s) (0.15 m) = 1.71 m/s For pendulum 6, the maximum speed is s2gh 2(9.8 m/s) (0.6 m) = 3.43 m/s Therefore, the rank of pendulums from largest to smallest is 1-6>2>3=4>5.

Answer 2

there is a mistake in the answer above in part c