Question

For a confidence level of 92%, find the critical value Question 5. Points possible: 1 This is attempt of

Answer 1

5).for 92% confidence interval the critical value is =
4151

[ in any blank cell of excel type =NORMSINV(0.96) ]

6).z critical value for 99% confidence level, both tailed test be:-

$z^*=2.576$

sample proportion ($\hat{p}$) = 280/500 = 0.56

sample size (n) = 500

the 99% confidence interval be:-

p(1-P) =P **

10.56(1-0.56) = 0.56 +2.576 + 500

10.503.0.617)

7).z critical value for 90% confidence level, both tailed test be:-

2* = 1.645

sample proportion ($\hat{p}$) = 0.47

sample size (n) = 410

the margin of error at 95% confidence level be:-

p(1-P) Vn

10.47(1-0.47) = 1.645 */ 410

0.041

6).z critical value for 99.9% confidence level, both tailed test be:-

=3.291

sample proportion ($\hat{p}$) = 0.419

sample size (n) = 117

the 99.9% confidence interval be:-

p(1-P) =P **

10.41911 -0.419) = 0.41943.291 *1 117

会 (0.269, 0.569)

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