27. Consider the reaction. NH,HS(s) NH3(g) + H2S(g) At a certain temperature, Ke-8.5 × 10-3 In...

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Question

27. Consider the reaction. NH,HS(s) NH3(g) + H2S(g) At a certain temperature, Ke-8.5 × 10-3 In a reaction mix- ture at this t

solid form or will some of the existing solid decompose as equilibrium is reached?

science chemistry

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Answer 1

Answer #1

Given that,

[NH₃ ] = 0.166 M

and [H₂S ] = 0.166 M

Q_c = [NH₃][H₂S] = 0.166 * 0.166 = 0.0276 M .... as activities of Solids is one, so [NH₄HS] = 1 and is not included in equation

Now, K_c = 8.5 *10^-3 < Q_c

Thus, we have more concentration of products than in the equilibrium position. so, reaction will shift backward forming more NH₄HS.

Hence, More solid will form as equilibrium is reached.

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Answer 2

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