Question

Given: Mass_1 = 0.106 kg; Mass_2 = 0.121 kg; Acceleration = 0.585 m/s^2; g = 9.8 m/s^2. What is the calculated applied force? (Neglect friction.) 0.133 N. (answer with three sig. figs.) Mass_1 = 0.111 kg; Mass_2 = 0.116 kg; Acceleration = 0.202 m/s^2; g = 9.8 m/s^2. What is the theoretical Newton's Second Law Force? (Neglect friction.) N.

Answer 1

according to Newton's second law

6)

$F=F_{1}+F_{2}\\ \\ F=0.106\times 0.585+0.121\times 0.585\\ \\ F=0.133N$

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7)$F=ma$

here the net force is

$F=F_{1}+F_{2}\\ \\ F=0.111\times 0.202+0.116\times 0.202\\ \\ F=0.0459N$

in three significant figure