Question

The magnitude of each force is 276 N, the force on the right is applied at an angle 35° and the mass of the block is 23 kg. TWhat is the magnitude of the resulting acceleration? Answer in units of m/s 2

0 0
Add a comment Improve this question Transcribed image text
Answer #1

from the given information. N 276 sin 350 +276 cos 350 [ 23 kg. 1276 u=0.193 276 Con 35 -0.193N-m9 2 N-mg + 276 Sin 35º = 0 N276 Con 35° - 0:193x 67.114 = 239 a=9.2666 mis?

Add a comment
Know the answer?
Add Answer to:
What is the magnitude of the resulting acceleration? Answer in units of m/s 2 The magnitude...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • What maximum acceleration can the truck have before the box slides backward? Answer in units of...

    What maximum acceleration can the truck have before the box slides backward? Answer in units of m/s2. 012 10.0 points Two blocks connected by a string are pulled across a rough horizontal surface by a force applied to one of the blocks, as shown. The acceleration of gravity is 9.8 m/s. 3 kg 6 kg u= 0.48 If each block has an acceleration of 3.3 m/s? to the right, what is the magnitude of the applied force?

  • A 2.74 kg block is pushed 1.41 m up a vertical wall with a constant speed...

    A 2.74 kg block is pushed 1.41 m up a vertical wall with a constant speed by a constant force of magnitude F applied at an angle of 66.3 with the horizontal. The acceleration of gravity is 9.8 m/s2. If the coefficient of kinetic friction between the block and wall 0.415, find the work done by F. A 2.74 kg block is pushed 1.41 m up a vertical wall with a constant speed by a constant force of magnitude F...

  • 1. A sliding block of mass m-0.25 kg is subject to a force of magnitude 4...

    1. A sliding block of mass m-0.25 kg is subject to a force of magnitude 4 N that makes an angle of p 30° with the horizontal surface. If the coefficient of kinetic friction between block and surface is 0.5, what is the resulting acceleration of the block along the surface?

  • A 2.0 kg block is pushed 2.0 m at a constant velocity up a vertical wall by a constant force applied at an angle of 25.0 with the horizontal

    A 2.0 kg block is pushed 2.0 m at a constant velocity up a vertical wall by a constant force applied at an angle of 25.0 with the horizontal, as shown in the figure. The acceleration of gravity is 9.81 m/s2.Drawing not to scale. If the coefficient of kinetic friction between the block and the wall is 0.40, find a) the work done by the force on the block. Answer in units of J b) the work done by gravity on the block....

  • Questions 1&2 FP 1. A sliding block of mass m 0.25 kg is subject to a...

    Questions 1&2 FP 1. A sliding block of mass m 0.25 kg is subject to a force of magnitude 4 N that makes an angle of ф-30 with the horizontal surface. If the coefficient of kinetic friction between block and surface is 0.5, what is the resulting acceleration of the block along the surface Figure 1: Block on incline. 2. A block of mass m - 5 kg is subject to a force of magnitude 20 N that makes an...

  • magnitude 7. An initially stationary block of mass m is on a floor. A force of...

    magnitude 7. An initially stationary block of mass m is on a floor. A force of acceleration due to gravity) is then applied at an angle of θ-20° to the oseontal, What is the magnitude of the acceleration of the block across the floor if p, 0.620 and p 0530 A) Om/s B) 005 m/s C) 2.17 m/s D) 0.20 m/s' E) 20 m/s 28. The same heavy wooden block is dragged by a force F along a rough steel...

  • A 17.5 kg block is dragged over a rough, horizontal surface by a constant force of...

    A 17.5 kg block is dragged over a rough, horizontal surface by a constant force of 70.4 N acting at an angle of 27.5◦ above the horizontal. The block is displaced 46.9 m, and the coefficient of kinetic friction is 0.119. The acceleration of gravity is 9.8 m/s2 . 17.5 kg μ = 0.119 Find the work done by the force of friction. Answer in units of J.

  • Given: Mass_1 = 0.106 kg; Mass_2 = 0.121 kg; Acceleration = 0.585 m/s^2; g = 9.8...

    Given: Mass_1 = 0.106 kg; Mass_2 = 0.121 kg; Acceleration = 0.585 m/s^2; g = 9.8 m/s^2. What is the calculated applied force? (Neglect friction.) 0.133 N. (answer with three sig. figs.) Mass_1 = 0.111 kg; Mass_2 = 0.116 kg; Acceleration = 0.202 m/s^2; g = 9.8 m/s^2. What is the theoretical Newton's Second Law Force? (Neglect friction.) N.

  • A 5.38 kg block is placed on top of a 9.24 kg block. A horizontal force...

    A 5.38 kg block is placed on top of a 9.24 kg block. A horizontal force of F = 70.6 N is applied to the 9.24 kg block and the 5.38 kg block is tied to the wall. The coefficient of kinetic friction between all moving surfaces is 0.28. There is friction both between the masses and between the 9.24 kg block and the ground. The gravity acceleration is 9.8 m/s^2. Determine the magnitude of the acceleration of the 9.24...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT