Question

What is the sign of AU as the system of ideal gas goes from point A to point B on the graph? (Hint the U is function of temperature only for a perfect gas) p (atm) 4 3 2 B V (m3) 1 2 3 4 The states And B have the same internal energy, so delta U is zero The internal energy of the system increases, so delta U is positive The internal energy of the system decreases, so delta U is negative

Answer 1

(atm) At paint A; PA 24 atly VA 2 L m3 . paint B; PB 2 L atun Vg24 MB At at so we w (4,1) vlms) 1 2 3 4 5 1 from ideal gas ean; PVZ MRT At A 2) PAVA 2 MRTA A mass is game for ASB At B 2) PB VBS MRTB systemy Naw; Taking ratio of both paint's egna I cet m PAVA MRTA ( R is same 2101.325 kPa) for same PBVB MRTR ( gus) .. 4x1x101.325x10 1 X 4 X 101.3254193 2 ( :(А - Тв) TA.. TB CMS

- so; 2) Temperature at bath section state is since Juternal energy of Ideal gas is of Temperature ouby. same. function OB for TB 2 TA 2) ( UBRUAT le for same Temperature at both paint. they are subjected to sound Tuter have same Internal energy. Į UB2UA 20 same Internal Energy / so; DUBA 2 NB-UA Apavu SDUBA 20/ & delta U is zero