Question

hello, I need help on solving the extra cradits.

i just need the screen shot if the code in MATHLAB with the plot regenerating the original signal using FT result.

pls make it simple and clear. if you dont know the answer dont replay.

thats my lab report page that i need to fill for the question so you can have a better picture on what you are working on.

thank you so much

3 Extra Credit . Now consider a -1 and there is no time shifting. Try to reproduce a(t) using Inverse Fourier Trans- form equation: Plot the reproduced signal (t) and the original signal r(t) on the same plot. Comment on their difference and how to improve the reproduced signal. Include your code and plot in the report. . Try to find one or two different signal from Fourier Transform table and plot their Fourier Transform according to the table. See what the difference comparing with the lab exercise. 4 Submission . Your cuode to weratte crst and i pant . Your calculation result of the FT of x(t). . The plot wng the abscolte valuts and phase for the FT . Extra credit(optional): Your code and plot regenerating the original signal using FT result

Answer 1

clc;close all;clear all;
t=-5:0.1:5;
x=sinc(t)
subplot(221)
plot(t,abs(x),'m')
xlabel('t')
ylabel('x(t)')
title('signal x(t)=sinc(t)')

k=0
for w=-pi:pi/200:pi
k=k+1
X(k)=trapz(t,x.*exp(-j*w*t))
endfor
w=-pi:pi/200:pi
subplot(222)
plot(w,abs(X),'r')
xlabel('w/pi')
ylabel('X(w)')
title('Absolute value of FT')

subplot(223)
plot(w,angle(X),'g')
xlabel('w/pi')
ylabel('X(w)')
title('Phase value of FT ')

k=0
for t=-5:0.1:5
k=k+1
xx(k)=(1/(2*pi))*(trapz(w,X.*exp(j*w*t)))
endfor
t=-5:0.1:5
subplot(224)
plot(t,xx,'b')
xlabel('w/pi')
ylabel('X(w)')
title('Orginal signal from Inverse Fourier transform')

signal x(t)-sinc(t) Absolute value of FT 0.8 0.6 0.4 0.2 0.8 0.6 0.4 6 4 4 2 4 Phase value of FT Orginal signal from Inverse Fourier transform 4e-016 3e-016 2e-016 1e-016 0.8 0.6 0.4 X0.2 -1e-016 2e-016 -3e-016 4e-016 0.2 0.4 2 2 4 6 -4 4 w/pi