Suppose a person can run 10 m/s. If all of that person's Kinetic energy turned into...
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Suppose a person can run 10 m/s. If all of that person's Kinetic
energy turned into...
A 70 kg person can achieve the maximum speed of 2.5 m/s while running a 100...
A 70 kg person can achieve the maximum speed of 2.5 m/s while running a 100 m dash. Treat the person as a point particle. a. At this speed, what is the person's kinetic energy? Express your answer with the appropriate units. b. To what height above the ground would the person have to climb in a tree to increase his gravitational potential energy by an amount equal to the kinetic energy you calculated in part A? Express your answer...
Based on your results. did all of the initial gravitational potential energy convert into kinetic energy?...
Based on your results. did all of the initial gravitational potential energy convert into kinetic energy? If there is a difference between the gravitational potential energy and the kinetic energy, what do you think caused the difference? Did the angle of the track or the mass of the cart have any effect on the data? Explain What were the sources of error m this experiment? How did your hypothesis compare to your conclusion? Hypothesis in winter ski jumping, how would...
How fast would a 89 kgkg person have to run to have a kinetic energy equal...
How fast would a 89 kgkg person have to run to have a kinetic energy equal to the amount of energy used by a 40 Watt light bulb in 16 ss ? How fast would a 89 person have to run to have a kinetic energy equal to the amount of energy used by a 40 Watt light bulb in 16 ? 2.6 m/sm/s 14 m/sm/s 3.7 m/sm/s 0.95 m/sm/s
Suppose a 0.390 kg ball is thrown at 17.0 m/s to a motionless person standing on...
Suppose a 0.390 kg ball is thrown at 17.0 m/s to a motionless person standing on ice who catches it with an outstretched arm as shown in the figure below. (a) Calculate the final linear velocity (in m/s) of the person, given his mass is 90.0 kg x m/s 07 (b) What is his angular velocity (in rad/s) if each arm is 3.00 kg? You may treat the ball as a point mass and treat the person's arms as uniform...
The world's fastest humans can reach speeds of about 11 m/s
The world's fastest humans can reach speeds of about 11 m/s. In order to increase his gravitational potential energy by an amount equal to his kinetic energy at full speed, how high would such a sprinter need to climb? How do you set this up?
Which of the following energy system(s) is (are) independent of orientation/direction? -Kinetic Energy (moving left vs...
Which of the following energy system(s) is (are) independent of orientation/direction? -Kinetic Energy (moving left vs right) -Rotational Kinetic Energy (spinning clockwise vs spinning anti-clockwise) -Spring-Mass Potential Energy (being compressed vs being stretched) -Gravitational Potential Energy (being 2 m above ground vs 2 m below ground) I thought it was kinetic energy and spring mass potential energy but is it also rotational energy?
In the high jump, the kinetic energy of an athlete is transformed into gravitational potential energy...
In the high jump, the kinetic energy of an athlete is transformed into gravitational potential energy without the aid of a pole. With what minimum speed must the athlete leave the ground in order to lift his center of mass 2.10m and cross the bar with a speed of 0.50 m/s?
In the high jump, the kinetic energy of an athlete is transformed into gravitational potential energy without the aid of a pole
In the high jump, the kinetic energy of an athlete is transformed into gravitational potential energy without the aid of a pole. With what minimum speed must the athlete leave the ground in order to lift his center of mass 2.00 m and cross the bar with a speed of 0.71 m/s?
P4. Use CONSERVATION OF ENERGY to determine how HIGH a projectile of mass m goes if...
P4. Use CONSERVATION OF ENERGY to determine how HIGH a projectile of mass m goes if STARTED with VELOCITY v0at angle q with respect to the ground. Please give all your answers below in terms of v0, q, m, and g .a) What is the KINETIC ENERGY at the start? b) What is the KINETIC ENERGY at the HIGHEST point of its flight? c) What is the GRAVITATIONAL POTENTIAL ENERGY at the start? d) What is the GRAVITATION POTENTIAL ENERGY...
Given the formula of the kinetic energy of a particle m with speed v: KE =...
Given the formula of the kinetic energy of a particle m
with
speed v:
KE = 1⁄2mv2 ,
and the formula of the gravitational potential energy:
PE = -GMEm/R,
where G is gravitational constant and ME and R=6378 km are the
mass and the radius of Earth. Now the particle is shot from Earth
surface to space. Find the minimum required initial speed for this
particle to completely escape the influence of Earth gravity (i.e.
PE=0). Notice that the gravitational...
Based on your results. did all of the initial gravitational potential energy convert into kinetic energy? If there is a difference between the gravitational potential energy and the kinetic energy, what do you think caused the difference? Did the angle of the track or the mass of the cart have any effect on the data? Explain What were the sources of error m this experiment? How did your hypothesis compare to your conclusion? Hypothesis in winter ski jumping, how would...
Suppose a 0.390 kg ball is thrown at 17.0 m/s to a motionless person standing on ice who catches it with an outstretched arm as shown in the figure below. (a) Calculate the final linear velocity (in m/s) of the person, given his mass is 90.0 kg x m/s 07 (b) What is his angular velocity (in rad/s) if each arm is 3.00 kg? You may treat the ball as a point mass and treat the person's arms as uniform...
Given the formula of the kinetic energy of a particle m
with
speed v:
KE = 1⁄2mv2 ,
and the formula of the gravitational potential energy:
PE = -GMEm/R,
where G is gravitational constant and ME and R=6378 km are the
mass and the radius of Earth. Now the particle is shot from Earth
surface to space. Find the minimum required initial speed for this
particle to completely escape the influence of Earth gravity (i.e.
PE=0). Notice that the gravitational...
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