In the high jump, the kinetic energy of an athlete is transformed into gravitational potential energy without the aid of a pole
Homework Answers
(1/2)mv² = (1/2)m(0.71)²+mg(2.00)
Solve for v.
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In the high jump, the kinetic energy of an athlete is transformed into gravitational potential energy without the aid of a pole
In the high jump, the kinetic energy of an athlete is transformed into gravitational potential energy...
In the high jump, the kinetic energy of an athlete is transformed into gravitational potential energy without the aid of a pole. With what minimum speed must the athlete leave the ground in order to lift his center of mass 2.10m and cross the bar with a speed of 0.50 m/s?
The figure is a graph of the gravitational potential energy and kinetic energy of a 70...
The figure is a graph of the gravitational potential energy and
kinetic energy of a 70 g yo-yo as it moves up and down on its
string. The acceleration of gravity is 9.81 m/s2 .
a) By what amount does the mechanical energy of the yo-yo change
after 6.0 s? Answer in units of J.
b) What is the speed of the yo-yo after 4.5 s? Answer in units of
m/s.
c) What is the maximum height of the yo-yo?...
The specialty of an athlete on the women's track team is the pole vault. She has...
The specialty of an athlete on the women's track team is the pole vault. She has a mass of 44 kg and her approach speed is 8.7 m/s. When she is directly above the bar, her speed is 1.7 m/s. Neglecting air resistance and any energy absorbed by the pole, determine the amount she has raised herself as she crosses the bar. m A roller coaster car is pulled up the first (biggest) hill, 103 meters above the subsequent bottom...
Based on your results. did all of the initial gravitational potential energy convert into kinetic energy?...
Based on your results. did all of the initial gravitational potential energy convert into kinetic energy? If there is a difference between the gravitational potential energy and the kinetic energy, what do you think caused the difference? Did the angle of the track or the mass of the cart have any effect on the data? Explain What were the sources of error m this experiment? How did your hypothesis compare to your conclusion? Hypothesis in winter ski jumping, how would...
(a) How much gravitational potential energy (relative to the ground on which it is built)
(a) How much gravitational potential energy (relative to the ground on which it is built) is stored in an Egyptian pyramid, given its mass is about 4 x 105kg and its center of mass is 19.0 m above the surrounding ground? (b) What is the ratio of this energy to the daily food intake of a person (1.2 x 107 J)
Given the formula of the kinetic energy of a particle m with speed v: KE =...
Given the formula of the kinetic energy of a particle m
with
speed v:
KE = 1⁄2mv2 ,
and the formula of the gravitational potential energy:
PE = -GMEm/R,
where G is gravitational constant and ME and R=6378 km are the
mass and the radius of Earth. Now the particle is shot from Earth
surface to space. Find the minimum required initial speed for this
particle to completely escape the influence of Earth gravity (i.e.
PE=0). Notice that the gravitational...
QUESTION 1 In pole vaulting, a jumper achieves great height by converting their kinetic energy of running in to gravita...
QUESTION 1
In pole vaulting, a jumper achieves great height by converting
their kinetic energy of running in to gravitational potential
energy. The pole plays an intermediary role in this process.
Suppose that a jumper runs at a speed of 9.1 m s-1, use a simple
model to estimate how far the jumper's centre of mass will rise.
(For reference only, a new world record was set in early 2014 of
6.16 m.)
QUESTION 2
A hoist system (see figure...
m, RU B2 8. An adjustable loop, with a cross-bar of width w that slides between...
m, RU B2 8. An adjustable loop, with a cross-bar of width w that slides between two rails, is tilted so that it makes an angle with respect to the ground. Let the sliding cross-bar have a resistance R and a mass m (and neglect any other resistance). a. If the loop is placed in a vertical magnetic field, B = Bỉ, show that the cross-bar does not keep accelerating, but reaches a terminal speed mgR sine B2w2 cos20 V...
Parallel Axis Theorem: I = ICM + Md Kinetic Energy: K = 2m202 Gravitational Potential Energy:...
Parallel Axis Theorem: I = ICM + Md Kinetic Energy: K = 2m202 Gravitational Potential Energy: AU = mgay Conservation of Mechanical Energy: 2 mv2 + u = žmo+ U Rotational Work: W = TO Rotational Power: P = TO Are Length (angle in radians, where 360º = 2a radians): S = re = wt (in general, not limited to constant acceleration) Tangential & angular speeds: V = ro Frequency & Period: Work-Energy Theorem (rotational): Weet = {102 - 10...
P4. Use CONSERVATION OF ENERGY to determine how HIGH a projectile of mass m goes if...
P4. Use CONSERVATION OF ENERGY to determine how HIGH a projectile of mass m goes if STARTED with VELOCITY v0at angle q with respect to the ground. Please give all your answers below in terms of v0, q, m, and g .a) What is the KINETIC ENERGY at the start? b) What is the KINETIC ENERGY at the HIGHEST point of its flight? c) What is the GRAVITATIONAL POTENTIAL ENERGY at the start? d) What is the GRAVITATION POTENTIAL ENERGY...
The figure is a graph of the gravitational potential energy and
kinetic energy of a 70 g yo-yo as it moves up and down on its
string. The acceleration of gravity is 9.81 m/s2 .
a) By what amount does the mechanical energy of the yo-yo change
after 6.0 s? Answer in units of J.
b) What is the speed of the yo-yo after 4.5 s? Answer in units of
m/s.
c) What is the maximum height of the yo-yo?...
Based on your results. did all of the initial gravitational potential energy convert into kinetic energy? If there is a difference between the gravitational potential energy and the kinetic energy, what do you think caused the difference? Did the angle of the track or the mass of the cart have any effect on the data? Explain What were the sources of error m this experiment? How did your hypothesis compare to your conclusion? Hypothesis in winter ski jumping, how would...
Given the formula of the kinetic energy of a particle m
with
speed v:
KE = 1⁄2mv2 ,
and the formula of the gravitational potential energy:
PE = -GMEm/R,
where G is gravitational constant and ME and R=6378 km are the
mass and the radius of Earth. Now the particle is shot from Earth
surface to space. Find the minimum required initial speed for this
particle to completely escape the influence of Earth gravity (i.e.
PE=0). Notice that the gravitational...
QUESTION 1
In pole vaulting, a jumper achieves great height by converting
their kinetic energy of running in to gravitational potential
energy. The pole plays an intermediary role in this process.
Suppose that a jumper runs at a speed of 9.1 m s-1, use a simple
model to estimate how far the jumper's centre of mass will rise.
(For reference only, a new world record was set in early 2014 of
6.16 m.)
QUESTION 2
A hoist system (see figure...
m, RU B2 8. An adjustable loop, with a cross-bar of width w that slides between two rails, is tilted so that it makes an angle with respect to the ground. Let the sliding cross-bar have a resistance R and a mass m (and neglect any other resistance). a. If the loop is placed in a vertical magnetic field, B = Bỉ, show that the cross-bar does not keep accelerating, but reaches a terminal speed mgR sine B2w2 cos20 V...
Parallel Axis Theorem: I = ICM + Md Kinetic Energy: K = 2m202 Gravitational Potential Energy: AU = mgay Conservation of Mechanical Energy: 2 mv2 + u = žmo+ U Rotational Work: W = TO Rotational Power: P = TO Are Length (angle in radians, where 360º = 2a radians): S = re = wt (in general, not limited to constant acceleration) Tangential & angular speeds: V = ro Frequency & Period: Work-Energy Theorem (rotational): Weet = {102 - 10...
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