Question

Draw the SFD and the BMD for the following beams

15kN/m 10kN LIT * 2m **Im * 1m (10) 10KN 5kN/m 5kN/m 2m 2m1m

Answer 1

I J 15 kN/m L J 4m hinge ß im lokn v c imod SFD parabola BMD 140 moment at tinge =0 Sto = – 5 kn (SEC) R = -5 kN SF) = 5kN Dy x2 = 10x1 Dy=5kn (SFelse = -5110=5kN STA=5+ 15x4 = 65kN {Fyzo; Aytby = 15x4 +0= 70 Ay = 70-5 = 65 kn EARD My =o (Roller) Me= 5x10 = 50 kN-m Me =0 Chinge) MA= 5x6 - 10x5 - 15x4x4 = - 140 kn-m

lokn skolm Skolm A J J J Je VC DIT 2 m SE 75 a parabolic BMD 25 The given Beam is symmetrical about loading ... By + Dy = 5x1+10+5x1 = 20 By = by= 20/2 = 10 kn SFA (SFB)JL = -5x = us kn (SFB) R = -5+10=5 KN (SF) = Ska (SF); R = 5-10 = -ska (Sto),L= us kn (SF) JR = 5+10= 5 kn MA=0 MB = – 5x1x & -2.5 kN-m Mc- +5x1x (+ 2) +10% 2 & 7.5 kN-m Mo= 5xx (²+4) + 10x4 - 10x2 S-25 kNm iste) =0