To determine the optimal number of items a company should hold in inventory, it is necessary to estimate the average weekly sales of that particular item. A random sample is taken, and the number of items sold per week is as follows: 64, 57, 49, 81, 76, 70, 59. Assume that the number of items sold is normally distributed. Give a point estimate and interval estimates for the mean number of items sold per week, assuming a 80%, 90%, 95% and 99% confidence level. Explain the meaning of your interval estimates.
= (64 + 57 + 49 + 81 + 76 + 70 + 59)/7 = 65.143
s = sqrt(((64 - 65.143)^2 + (57 - 65.143)^2 + (49 - 65.143)^2 + (81 - 65.143)^2 + (76 - 65.143)^2 + (70 - 65.143)^2 + (59 - 65.143)^2)/6) = 11.2462
At 80% confidence interval the critical value is t* = 1.440
The 80% confidence interval for population mean is
+/- t* * s/
= 65.143 +/- 1.440 * 11.2462/
= 65.143 +/- 6.121
= 59.022, 71.264
We are 80% confident that the true population mean number of items sold per week lies in the above interval
At 90% confidence interval the critical value is t* = 1.943
The 90% confidence interval for population mean is
+/- t* * s/
= 65.143 +/- 1.943 * 11.2462/
= 65.143 +/- 8.259
= 56.884, 73.402
We are 90% confident that the true population mean number of items sold per week lies in the above interval
At 95% confidence interval the critical value is t* = 2.447
The 95% confidence interval for population mean is
+/- t* * s/
= 65.143 +/- 2.447 * 11.2462/
= 65.143 +/- 10.401
= 54.742, 75.544
We are 95% confident that the true population mean number of items sold per week lies in the above interval
At 99% confidence interval the critical value is t* = 3.708
The 99% confidence interval for population mean is
+/- t* * s/
= 65.143 +/- 3.708 * 11.2462/
= 65.143 +/- 15.761
= 49.382, 80.904
We are 99% confident that the true population mean number of items sold per week lies in the above interval
To determine the optimal number of items a company should hold in inventory, it is necessary...
Please show how you did this in excel.
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