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1. For each system of linear equation, find the solution by Gaussian (set up the augment matrix, forward elimination to find
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Answer #1

@ (I) 23-y-Z = 2 42 - 22 = -1 x + 4y +z = 4 ] can be written as. Az = b. [ 2 -1 717 | 4 o - 29 Į 4 1 Vī Consider the augmente[ 4 14 lo at - 1 - 1 - 1 -q -3 1-6 =R3 - 9 R2 To 0 -1 -% - 0 38 1 57 System I reduces to. 2 + 4y + z = 4 -yz = -1 .... 0 Putt& Solution is Augmented matrix 2 -2 S!-0 - 0 I NOW 2 1 3 -2] RE cm 2 - 0 2 3 1-2 0 2 11-2 R₂-2R, To ao 1 ² R2+28,7 loi į To -=> dz= +2 = 846. - putting w in y + (- 3) = 1 => y = 1+ g = Putting z in (i) = + 3 = 3. a- = in Solution is ADN 3

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