Answer : - 37.2 oC
mass of ethylene glycol = 620.0 g
moles of ethylene glycol = 620 / 62.07 = 9.99
mass of water = 500 g = 0.5 kg
molality = moles / mass of solvent
= 9.99 / 0.5
molality = 19.98 m
delta Tf = Kf x m
0 - Tf = 1.86 x 19.98
Tf = - 37.2
freezing point = - 37.2 oC
Moving to another question will save this response. «. Questio Question 2 4 points Calculate the...
29) A solution is 0.0433 m LiF. What is the molarity of the solution if the density is 1.10 g/mL? A) 0.0441 M B) 0.0390 M C) 0.0476 M D) 0.0417 M E) 0.0519 M 30) Determine the freezing point depression of a solution that contains 30.7 g glycerin (C3H8O3, molar mass =92.09 g/mol) in 376 mL of water. Some possibly useful constants for water are Kf 1.86°C/m and Kb 0.512°C/m. A) 3.33°C B) 0.654°C C) 1.65°C D) 4.95°C E)...
A solution of ethylene glycol in water at 20 degrees celsius has a mass percent of 9.78% of ethylene glycol with a density of 1.0108 g/mL. The freezing point depression constant for water (solvent for all solutions) is Kf=-1.86 percent celsius kg/mol and the boiling point elevation constant is Kb=0.512 degrees celsius kg/mol. The density of neat water at 20.0 degrees celsius is 0.9982 g/mL. Answer the following: 1. What is the molarity of the solution? 2. What is the...
What is the freezing point and boiling point in Celsius of a solution 400 g of ethylene glycol (MW=62 g/mol) dissolved in 500 g of water? The molal freezing point depression constant for water is 1.86 C/m The molal boiling point elevation constant of water is 0.512 C/m Please explain steps
Ethylene glycol is used in automobile radiators as an antifreeze. Use the following information to determine the freezing point of an antifreeze solution made by mixing 2.5 L of ethylene glycol with 2.5 L of water. Ethylene glycol is essentially nonvolatile and it does not dissociate in water. Molar mass of ethylene glycol = 62.1 g/mol; density of ethylene glycol = 1.11 g/mL; density of water = 1.00 g/mL; Kf for water = 1.86 degrees Celsius kg/mol
A 15.3 g sample of a compound known to contain 3 ion species is dissolved in 110 g of water. The boiling point of the solution is 103.0 degrees Celsius. What is the molar mass of the compound? Additional Info: Physical Properties of water Freezing point: 0.00 degrees Celsius Boiling point: 100 degrees Celsius Kf: 1.86 Degrees Celsius/m Kb: 0.512 degrees Celsius/m
(2) (4 points) Ethylene glycol (C,HO2) is a molecular compound that is used in many commercial anti-freezes. A water solution of ethylene glycol is used in vehicle radiators to lower its freezing point and thus prevent the water in the radiator from freezing. Calculate the freezing point of a solution of 350.0 g of ethylene glycol in 900.0 g of Kxkg water. Rationalize your answer. Ky(water)= 1.86
0 Question 36 6 pts What is the freezing point of a solution prepared from 50.0 g ethylene glycol (C2H602) and 85.0 g H202 (For water, K - 1.86°C/m) 0 -17.6°C O-176°C O -1.50°C O 17.6°C O 1.50°C Question 37 10 pts
Question 2 (10 points) Calculate the freezing point of a solution that contains 5.78 g of glucose, a non- electrolyte, dissolved in 130 g of water. Note: Kf for water is 1.86°C/m
Moving to another question will save this response. Question 3 Question 3 of 23 Next Questio 5 points Saver Company Shoes, Inc. is considering replacing it current shoe packing machine with a new one. The estimated costs are provided below. What is the future worth of the new machine If the company's rate of return is 10% per year? (closest answer First costs Annual operating cost $ per year Life years 15244.2 33489.9 23489.9 12453.6
Calculate and enter the freezing point depression of a solution of 73.2 g ethylene glycol (C2H602) in 561 g H20. Kffor H20 is 1.86 °C kg/mol. °C 1homework pts Submit Answer Tries 0/5 A solution which contains 43.6 g of an unknown molecular compound in 339 g of water freezes at -4.85°C. What is the molar mass of the unknown? g/mol