Question

In the figure, two point charges q1 = 1.70×10^-5C and q2 = 6.80×10^-5C are separated by a distance d = 0.10 m. Compute their net electric field E (x) as a function of x for the following positive and negative values of x, taking E to be positive when the vector E points to the right and negative when E points to the left. Plot your values in your notebook.

a. What is E(0.070)?

b. What is E(0.090)?

c. What is E(0.110)?

d. What is E(0.150)?

Please help!! Thank you

Answer 1

X= 0.07 m d = 0. 10 m 92= 1.7x105c E- E lectnic field due to 42 E -- Electnic field due to 12 Elo.07)= E- K→ electno static K22 %3D Constant (d-n)? K- 9x1.9 Nm² C2 Kſ 1:7x155- 6-8×105 gx10° x 1.7 x1 ५१४१५ 15.3 x 10° 49 81 15:3 x18 (-0-029 N/C -0.4437 x1. N/c ·4.437 x 10* C E pointa to Deft Tu',

O E(0010) = E-Ez (d-x)= х2 d-x) = 9x10% 6.8 x LoS (0.01)2 1:7 x 10 9x10' x 1.7 x 1ó 81 x154 15-8 x1.3 15-8 x 16° x (-3-98) N/C - 62. 13 x1.3 Nc N/C E þoints to left O E(o. 110) = ELt Ez = KL + K92 x2 -d. sto

|-7x105 Ix10" 6. 8 x Lo 121x154 gx40" x 1:7x155 (21 15:3 x 1. ( 4 -008) 6 1.33 x 1.3 Nic þoints to Dight O E(O-15) = E1+ Ez K92 x-a)2 92 0-15-019 @-15)2 Ix1. 1-7x155 225 x159 6-8 x155 N/C 9メ16×1-子xi。 25 x 159 2. 516 x 10° N/c E þein ta to gright