Question

1. For the following nominal sizes of fillet welds determine: a) The throat thickness b) The safe load (N/mm), weld material = 410MP and FoS=3. Nominal size (mm) 4681012 1620 24 Throat thickness (mm) Safe load (N/mm) Note: These results can be used to solve the remainder of problems. Answer N/mm mm |2.8 387 4.2 580 5.7 773 7.1 966 8.5 1160 11.3 1550 14.1 1930 17.02320 2. A 100mm wide and 10mm thick steel strap is to be welded to a heavy steel plate as shown below, determine the length (L) of the 8mm fillet weld to withstand a total load of 150kN -150Kn

Answer 1

Nominal thickness - h throat thickness a h crs 45° Vz = 707h throat area = .707 hxe i. p= {x. 707hl 2) Ple: 707 h XI. fillet weld I allowake = 410 = 136.67 apa 17 ha 4 mm throat thickness (t) = b = .707h 3 2.82 mm safe load (P = .707X 48 136.67 = 386.5 N/mm h = 6 mm ta.707 h = 4.24 mm safe load = .7078 6x136.67 =579.8 N/mm lliy ha 8mm ta 707 h - 5.65 mm. safe load = .7078 hx 2 = 773 N/mm. Tuy h= 10mm t=.707h : 7.07 mm safe load 2 7078 10x136.67 = 96 6.25 N/mm

quy h= 12 mm I ta 707 ha 8.48 mm I safe load a 707 x hx I - 1159 15 N/mm. zviy ha 16mm ta 7078 16 2 11 31 mm safe load a 707h I = 1546 N/mm. ruiiy h= 20mm. t = 707h a 14. 14 mm safe load = .7074hX I = 1932 N/mm. <viliy ha 24 mm ta.707 h a 16.96 mm Safe load - 707 xh XI = 2319 N/mm. Nominal size of weld = 8mm. so total throat area - 2 x 1.707 xh XL) 1 bedause welds are on both side o. P= 2x.7078hX LX I from question 1) taking I = 136.67 9 Ra and p = 150 x 103 N . L = P 150x103 - 97.02 mm 1.414 XhX I 1.414 X 8 X 136.67 so the length should be 97.02 mm