An rms voltage of 22.8 V with a frequency of 1.50 kHz is applied to a 0.250 mH inductor.
A.What is the rms current in this circuit? (In Amperes)
B.By what factor does the current change if the frequency of the voltage is doubled?
Impedence = Inductive reactance XL = wL = 2pif L
XL = 2* 3.14 * 1500 * 0.25 e -3
XL = 2.355 Ohms
SO Current Irms = Vrms/XL = 22.8/2.355
Irms = 9.68 Amps
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if f doubled wL also doubled
if V is doubled
then Irms 2V/2xL = 9.68 Amps
so remains same
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