Solve the following initial value problem: Sear= -3y + 15 1 y(0) = 8 y(t) =
15. (8 points) Solve the initial value problem y" + 4y' + 3y-хез®, y(0) 1, y'(0) 0
Solve the initial value problem y" + 3y' + 2y = 8(t – 3), y(0) = 2, y'(0) = -2. Answer: y = u3(t) e-(-3) - u3(t)e-2(1-3) + 2e-, y(t) ={ 2e-, t<3, -e-24+6 +2e-l, t>3. 5. [18pt] b) Solve the initial value problem y' (t) = cost + Laplace transforms. +5° 867). cos (t – 7)ds, y(0) – 1 by means of Answer:
Solve the following initial-value problem. y" + 3y + 4y = 282(t) - 385(t) y(0) = 1, y'(0) = -2
Solve the initial value problem. y'" – 3y" - y' + 3y = 0; y(0)=5, y'0) = -3. y'(0)=5 The solution is y(t) =
Consider the initial value problem y" +3y' +2y = (t-1)+r(t), y(0) = y(0) = 0, where 8(t-1) is Dirac's delta function and S4 if 0<t<1 r(t) 8 if t > 1 (a) Represent r(t) using unit step functions. (b) Find the Laplace Transform of 8(t-1)+r(t). (c) Solve the above initial value problem. {
#6 Solve the initial value problem y(0)- 2, y,(0) 1 y"-3y' + 2y-6(t-3);
9. Solve the initial value problem using the Laplace transform y" + 3y = f(t), y(0) = 0, y(0) = 1, where f(t) = { ( 1 home s 2, if 0 <t<5 1, if t > 5 (6
5. (11 points) Solve the following initial value problem, y" + 3y + 2y = g(t); y(0) = 0, 7(0) = 1/2 where g(t) = 38(t - 1) + uz(t) Type here to search
(1 point) Use the Laplace transform to solve the following initial value problem: y" + 3y = 0 y(0) = -1, y(0) = 7 First, using Y for the Laplace transform of y(t), i.e.. Y = C{y(t)} find the equation you get by taking the Laplace transform of the differential equation = 0 Now solve for Y (8) and write the above answer in its partial fraction decomposition, Y(s) Y(8) = B b where a <b sta !! Now by...
(1 point) Consider the initial value problem y' + 3y = 0 if 0 <t <3 9 if 3 < t < 5 0 if 5 <t< oo, y(0) = 3. (a) Take the Laplace transform of both sides of the given differential equation to create the corresponding algebraic equation. Denote the Laplace transform of y by Y. Do not move any terms from one side of the equation to the other (until you get to part (b) below). y(s)(5+6)...