Question

Solve fore Vb, Vc, Ib, Ic

hfe = 200

D. Voltage-divider Bias +10V R = 10k 2 < Rc = 3.9k22 2N3904 } RE = 1622 3R2 =2.2K12 = Figure 5.4

Answer 1

tlov Therenin's resistance, Rc = 3.962 Roth = 1-10kr R, R2 .R1+R2 the = 200. - K2 2.2k2 TO 2.2 10+2.2 = 1.80328 KM Yth = voltage accross R₂ = Vo. ..h = - - R₂ Ri+R₂ ? -x 10 = 2.2 2.2 10V =1080328 volt. The Ciruit will become,

Rih Skr +10V assuming Noe = 0.76 & RC=3•gkor VB - Ponto - VBET REIE =o ont 1080328 - 1.80328 Ig -0.7-1(heet) [p = 0 or, 1080328 – 1.803285,-0.7-(201) IR FO; : IE 1.80328 - 0.7 MA= 544 x16'ma 1080328 + 201 Ig = (hte + ) Ig = 201* 544X163 mA = 1:09347 mA .. Ic = It - IB = 1.09347 - (544x103) MA - 1.088029 mA. .. VB = 1180328V IB = 5:448103 mA = 5.444A Il = 1.088029 MA I = 1:09347mA