Question

Problem 3 A three-phase, 230-V, 60-Hz, 12-kW, four-pole wound-rotor induction motor has the following parameters expressed in

0 0
Add a comment Improve this question Transcribed image text
Answer #1

The following code is used to get the desired characteristics.

% First, initializing the values needed in the program.

Rs = 0.095; % Stator resistance

Xs = 0.680; % Stator reactance

Xr = 0.672; % Rotor reactance

Xm = 18.7; % Magnetization branch reactance

v_phase = 230 / sqrt(3); % Phase voltage

N_sync = 1800; % Synchronous speed (r/min)

w_sync = 188.5; % Synchronous speed (rad/s)

% Calculate the Thevenin voltage and impedance from Equations

V_th = v_phase * ( Xm / sqrt(Rs^2 + (Xs+ Xm)^2) );

Z_th = ((j*Xm) * (Rs+ j*Xs)) / (Rs+ j*(Xs+ Xm));

R_th = real(Z_th);

X_th = imag(Z_th);

% Now calculate the torque-speed characteristic for many
% slips between 0 and 1. Note that the first slip value
% is set to 0.001 instead of exactly 0 to avoid divide-
% by-zero problems.

s = (0:1:50) / 50; % Slip
s(1) = 0.001;
nm = (1 - s) * N_sync; % Mechanical speed
  
Rr = 0.1;

% Calculating torque

for ii = 1:51

t_ind(ii) = (3 * V_th^2 * Rr/ s(ii)) / (w_sync * ((R_th + Rr/s(ii))^2 + (X_th + Xr)^2) );

end

% Plot the torque-speed curve for R2=0.1

plot(nm,t_ind);

hold on;

Rr = 0.2;

% Calculating torque

for ii = 1:51

t_ind(ii) = (3 * V_th^2 * Rr/ s(ii)) / (w_sync * ((R_th + Rr/s(ii))^2 + (X_th + Xr)^2) );

end

% Plot the torque-speed curve for R2=0.2

plot(nm,t_ind);

Rr = 0.5;

% Calculating torque

for ii = 1:51

t_ind(ii) = (3 * V_th^2 * Rr/ s(ii)) / (w_sync * ((R_th + Rr/s(ii))^2 + (X_th + Xr)^2) );

end

% Plot the torque-speed curve for R2=0.5

plot(nm,t_ind);

Rr = 1;

% Calculating torque

for ii = 1:51

t_ind(ii) = (3 * V_th^2 * Rr/ s(ii)) / (w_sync * ((R_th + Rr/s(ii))^2 + (X_th + Xr)^2) );

end

% Plot the torque-speed curve for R2=1

plot(nm,t_ind);

Rr = 1.5;

% Calculating torque

for ii = 1:51

t_ind(ii) = (3 * V_th^2 * Rr/ s(ii)) / (w_sync * ((R_th + Rr/s(ii))^2 + (X_th + Xr)^2) );

end

% Plot the torque-speed curve for R2=1.5

plot(nm,t_ind);

xlabel('N_m(RPM)','Fontweight','Bold');

ylabel('\tau_{ind}(Nm)','Fontweight','Bold');

title ('Induction Motor Torque-Speed Characteristic','Fontweight','Bold');

legend ('R2=0.1','R2=0.2','R2=0.5','R2=1','R2=1.5');

grid on;

hold off;

By executing the above code in MATLAB we get following plot.

100 Induction Motor Torque-Speed Characteristic R2-0.1 R2-0.5 ーR2-1.5 90 -R2-0.2 80 70 60 弖50 30 20 10 200 600 800 1000 1400

Add a comment
Know the answer?
Add Answer to:
Problem 3 A three-phase, 230-V, 60-Hz, 12-kW, four-pole wound-rotor induction motor has the following parameters expressed...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT