Given that 0.4 ppm of Lead in Blood = 0.4 g of Lead in 1000000 g of Blood
So, 0.62 ppm of Lead in Blood = 0.62 g of Lead in 1000000 g of Blood
Conversely, 1000000 g of Blood = 0.62 g of Lead
Implies, 1 g of Blood = (0.62/1000000) g of Lead
Therefore, 6000 g of Blood = [(0.62 6000)/1000000] g of Lead
= 3.72 10-3 g of Lead is present in 6 103 g of Blood
HW 1c Question 2 (of 8) value: 10.00 points 1 out of 3 attempts Enter your...
PHYSICS ork Chapter 16 Question 3 (of 10) value: 10.00 points 1 out of 8 attempts ASSistance Two Styrofoam balls with the same mass m 7.40x10 kg and the same positive charge 0 are suspended from the same point by insulating threads of length L -0.950 m (the figure below). The separation of the balls isd -0.0300 m. What is the charge e? Check My Work View Hint View Question Show Me Guided Solution Practice This Quest Print Question Help...
ID Problems 46) A piece of silver (Ag) metal weighing 194.3 g is placed in a graduated cylinder containing 242.0 mL of water. The volume of water now reads 260.5 mL. From these data calculate the density of silver 47) The following procedure was used to determine the volume of a flask. The flask was weighed dry and then filled with water. If the masses of the empty flask and filled flask were 56.12 g and 87.39 g, respectively, and...
HM 202-001 HW Chapter 12 Question 3 (of 14) value: 0.00 points 2 attempts left Check my work Enter your answer in the provided box. How many grams of urea I(NH2)2CO] must be added to 495 g of water to give a solution with a vapor pressure 2.41 mmHg less than that of pure water at 30°c? (The vapor pressure of water at 30°C is 31.8 mmHg.) References eBook & Resources Multipart Answer Difficulty: 2 Difficulty: Medium
ment 05: Trusses and Frames Question 4 (of 8) value: 10.00 points 1 out of 3 attempts Do not round intermediate calculations, however for display purposes report intermediate steps rounded to three significant figures. Give your final answer(s) to three significant figures. Determine the force in members DE and D F of the truss shown when P 23 kips. 9 ft 6panels a 8 ft = 48 ft FDE kips kips References eBook & Resources Multipart Answer Chapter: 6-Analysis of...
omework 3 Question 1 (of 8) value: 12.50 points 2 out of 3 attempts A cold air-standard cycle with variable specific heats is executed in a closed system and is composed of the following four processes: 1-2 v constant, heat addition from 14.7 psia and 80°F in the amount of 260 Btu/lbm 2-3 P constant, heat addition to 3,200 R 3-4 Isentropic expansion to 14.7 psia 4-1 P-constant, heat rejection to initial state (a) Calculate the total heat input per...