What is the inductance of a series RL circuit in which R = 1.0 KΩ if the current increases to one-third of its final value in 30 μs? 74 mH 99 mH 49 mH 62 mH none of the above
1)What is the output
voltage V0 if op-amp is ideal?
R1= 2 KΩ, R2=8 KΩ, R3=3.2 KΩ, R4=6 KΩ, R5=19
KΩ, R6=4.6 KΩ, RL=9.6 KΩ, V1=1V, I2=0.5 mA and V3=2.5 V.
2) for the same circuit, R1= 2 KΩ R2=8
KΩ, R3=3.6 KΩ, R4=6 KΩ, R5=16.9 KΩ, R6=15 KΩ, RL=10 KΩ, V1=1V,
I2=0.5mA and V3=2V. What is the input impedance as
seen by source V3?
+ | R1 ہی ہے۔ ۸۸۸ ة -(1+ R5 | + ابرها -
3. .) In the circuit below, k, = 1 mA/V2, Vt = 1V, VDD = 11V, RL = 1 kΩ a.) Show that the transistor is in Cut off when S1 is connected to A. b.) Show that the transistor is in Ohmic Mode when S1 is connected to B and find RDS, ID, VSD, and Vo 싱, S1 0 80 Vo RL ウ
3. .) In the circuit below, k, = 1 mA/V2, Vt = 1V, VDD = 11V,...
In the circuit below v1 = 45 V, v2 = -60 V, v3 = 15 V, R1 = 6.3 kΩ, and R2 = 4.9 kΩ.Transform the left two practical voltage sources in the circuit below into practical current sources. Combine resistors and ideal current sources and then transform the resultant practical current source into a practical voltage source. Finally, combine the ideal voltage sources.(a) If RL = 7.4 kΩ, find the power delivered to it.(b) What is the maximum power...
In the circuit shown, R₁ = 20 kΩ and R₂ = 10 kΩ.The voltage at terminal B can be varied from minimum (wiper moves towards resistor R₂) to maximum (wiper moves towards resistor R₁) by rotating the potentiometer shaft.
The circuit below uses an ideal opamp. Find the value of RL such that Vo is not lower than -11.88 V Your answer should be expressed in kΩ and given to two decimal places. R, IL 100Ω 10 k2
In the CS amplifier shown in the figure above, Rsig =
20 kΩ amplifier input resistance Rin = 80 kΩ,
Cgs=2pF, Cgd= 0.5pF, gm=2mA/V,
ro= 80 kΩ , RD = 5 kΩ, and RL = 10
kΩ. (π = 3.14)
a) Determine high frequency cut-off fH.
(Use Miller Approximation. Use . as the
decimal point. Answer in MHz; for 7.89MHz write 7.89
only.)
VOD RD V RIS R CS V Ro In the CS amplifier shown in the figure above....
please help
Figure 1: RC Circuit RL Circuit 22 kΩ Figure 2: square V in V in square 100 kHz C1 1 nF 100 mH Tasks 300 Hz 1. (Pre-Lab Homework) Derive natural response voltage equation for RC circuit. 2. (Pre-Lab Homework) Derive step response voltage equation for RC circuit. 3. For V , use Arbitrary Function Generator with Square function, Frequency = 100kHz, Amplitude 1V, offset = 0.5V, Select your circuit components as R-1 kΩ and C-1nF. As Equation...
Question 2 • Find the time constant for the circuit below 10 kΩ Λ 20 kΩ Λ 100 pF - ξ 40 ΕΩ 3 30 ΚΩ
+9 V 10 kΩ 10 kΩ Rsig 50Ω 0.5 mA 7 si in For alpha - 0.99 and assuming r, is very large, find Rn O 101.8 ohms O 51.3 ohms ○ 5.18 kohms O 51.8 ohms
+9 V 10 kΩ 10 kΩ Rsig 50Ω 0.5 mA 7 si in For alpha - 0.99 and assuming r, is very large, find Rn O 101.8 ohms O 51.3 ohms ○ 5.18 kohms O 51.8 ohms