a. P(A) = 2/7 = .29, P(B) = 2/7 = .29,P(C)= 3/7 =.43
b.P(A U B) = P(A) + P(B) = .29+.29= .58
A and B are mutually exclusive
c. Ac = [E3, E4, E5, E6, E7] answer - iii
Cc= [E1, E4,E6,E7] answer - V
P(Ac) = 1 - P(A) = 1-.29 = .71
P(Cc) = 1 - P(C) = 1- .43 = .57
d. A U Bc
here A =[E1, E2], Bc = [E1,E2, E5, E6, E7]
A U Bc = [E1,E2, E5, E6, E7] answer - i
P (A U Bc) = P(A) - P(A n B)
here A and B are mutually exclusive So A n B = 0
P(A U Bc) = .29-0 = .29
Suppose that we have a sample space with seven equally likely experimental outcomes: E1, E2, Es,...
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