Shear strength = 2.6*10^9 Pa
thickness = t = 1.9 cm
Area = A = 102 cm^2
shear stress is the measure of the material's resistance to
cause "sliding" motion of its layers.
Since the hero has to take a cylindrical piece of metal out, the
area which will cause this force is 2*pi*r*t
r = sqrt(A/pi) = 5.7 cm = 0.057 m
Then so the force required is shear strength into this area = 2.6*10^9*2pi*0.057*0.019 = 17.7*10^6 N
Comic-book superheroes are sometimes able to punch holes through steel walls. (a) If the ultimate shear...
Comic-book superheroes are sometimes able to punch holes through steel walls.(a) If the ultimate shear strength of steel is taken to be 3.00 109 Pa, what force is required to punch through a steel plate 2.00 cm thick?Assume the superhero's fist has cross-sectional area of 1.10 102 cm2 and is approximately circular.(b) Qualitatively, what would happen to the superhero on delivery of the punch? What physical law applies?
auge Steel Framing Details 1. Complete all light g auge steel componente ir the following wall section, including floor joists, wall studs, roof rafters, and required clips angles, stiffeners, and fasteners. Label all components. Roof sheathing Wall sheathing 。 Interior wallboard Subflooring Foundation 103 Scale: l square =2" (50 mm) Name: necessity of cutting holes in m on the construction ste 12.11. 12.15). Thack etions a sed for top and bottom plates, e construction, shemperature that col tural shapes. Prers...