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50 mL of a 0.050 M solution of Cu2+ was reduced to solid copper. How many...

50 mL of a 0.050 M solution of Cu2+ was reduced to solid copper. How many coulombs had passed when the Cu2+ was completely reduced to Cu(s)? Use 2 significant figures. Please show all work, thank you!

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Step 1: Balanced Half-reactions: 1 Cu2 (aq) 2 e(aq)1 Cu(s) Cathode: Following stoichiometry of balanced reaction, transfer of reduces 1 m Cu2+(aq) 2 mol e # Mol of Cu2+ reduced = Molarity x Vol. in liters 0.050 M x 0.050 L = 0.0025 mol # Mol of electrons transferred during the process = 2 x mol of Cu2+(aq) 2 x 0.0025 mol-0.0050 mol Step 2: # 1 mol of electrons carries a charge of 1 faraday (-96485 C) # Total charge flown = 96485 C mol-1 x 0.0050 mol 482.43 C = 4.8 E+02 C

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