Ans :- The element of the period 2 is Carbon
Explanation :-
Because carbon carry 4 electrons in its valence shell (1s22s22p2), therefore value of 5th ionization energy i.e. I.E5 for carbon will be very high (as shown in the graph) as carbon carry the noble gas electronic configuration of He i.e. 1s2 after removing 4 electrons. So, I.E5 of carbon will be very high. Hence, the given element of period 2 will be Carbon.
The first five ionization energies (IE through IEs) of a Period 2 element have the following...
To UMOWw26urt twowilgoce Objective Knowledge Check Question 17 The first five ionization energies (IE, through IE,) of a Period 2 element have the following pattern: kJ/mol IE, IE, IE; IE4 IES Make a reasonable guess about which element this is. Enter its chemical symbol below. X 5 ? I Don't Know Submit 2010 Mo dica Type here to search
Question 6 0.15 pts Consider the following set of successive ionization energies: IE1 = 578kJ/mol IE2 = 1,820kJ/mol IE3 = 2,750kJ/mol IE4 = 3,600kJ/mol IE5 = 13,300kJ/mol To which second period element do these ionization values belong? Enter your answer as a chemical symbol (ex: He).
Please explain 25) What period 3 element has the following ionization energies (all in kJ/mol)? 25) IE1 - 738 IE2 14450 IE3 16400 IE4 17600 IE5-18820 IE6 19900 A) P B) Si C) CI D) Mg E) Na
Consider the following set of successive ionization energies: IE1 = 578kJ/mol IE2 = 1,820kJ/mol IE3 = 2,750kJ/mol IE4 = 11,600kJ/mol IE5 = 13,300kJ/mol To which second period element do these ionization values belong?
4. Consider an element of Period 2 which has the following successive ionization energies, in kJ/mol. What is the charge of the common ion? IE1, 1314 IE2, 3389 IE3, 5298 IE4, 7471 IEs, 10992 IE6, 13329 IE7, 71345 IE8, 84087 (1) -1 (2) –2 (3) –3 (4) +6 (5) +7
Ionization. 25. (3) Which of the following most likely represents the successive ionization energies (IE, through IE) of a noble gas in Period 4, in kJ/mol? (select the best one) IE IE2 IE3 IE4 IES a) 1351 2350 3565 5070 6240 941 2045 2973 4144 6590 c) 419 3052 4420 5877 7975 d) 590 1145 4912 6491 8153
a new element X is discovered that has the following successive ionization energies (kj/mol) IE1=1004 , IE2=1251 IE3=5988 , IE4=6220 , IE5=6803 , IE6=7178 a. what group (column) do you expect this element will belong? explain b. if this element X combined with fluorine , what is the likely molecular formula?( for example XF2, X2F3, etc)
Write the full electron configuration of the period 2 element with the following successive IEs (in kl/mol) IE1-73, IE2-2427, IE3-3659, IE425,022, IE5-32,22
Which element in row two would have the following ionization energies? Ionization energies are given in kJ/mol. IE3 = 4.58, IE4 = 7.48, IE5 = 9.44, IE6 = 53.27
10.) Below is a list of successive ionization energies (in kJ/mol) for a period 3 element. Identify the element and explain how you came to that conclusion. IE2 = 2250 IE3 - 3360 TE 4 = 4560 IE5 = 7010 IE6 - 8500 IE 7 = 27,100