Using the black box model of lens, calculate the image coordinates of object points shown in the figure. The focal length f of the lens is 10. The coordinate is defined as (s-value, height)
The mirror equation expresses the quantitative relationship between the object distance (do), the image distance (di), and the focal length (f). The equation is stated as follows:
The magnification equation relates the ratio of the image distance and object distance to the ratio of the image height (hi) and object height (ho). The magnification equation is stated as follows:
Using the black box model of lens, calculate the image coordinates of object points shown in...
Problem 4 (10 points) A thin converging lens has a focal length 6.0 cm. An object of height 2.0 cm is located 3cm in front of the lens as shown below 1) Draw a ray diagram to show the image position and size. 2) Calculate the image position and size using lens equations. -6em, 4em h-2cm f-6cm f-6cm s 3cm
3. Figure shows an object and its image formed by a thin lens. (a) What is the focal length of the lens and what type of lens (converging or diverging) is it? (b) What is the height of the image? Is it real or virtual? Draw a principal-ray diagram showing the formation of the image. -35.0 cm- Optic Object 15 Lens El crn Image 4. Figure shows an object and its image formed by a thin lens. (a) What is...
An object is located 26.0 cm from a certain lens. The lens forms a real image that is twice as high as the object. What is the focal length of this lens? Now replace the lens used in Part A with another lens. The new lens is a diverging lens whose focal points are at the same distance from the lens as the focal points of the first lens. If the object is 5.00 cm high, what is the height...
help Table 1: One Lens (18 points) Object Image Image Distance Distance Height Object Distance Image Distance Image Height (cm) (cm) (cm) (cm) (cm) (cm) 100.00 17.50 15.00 14.00 80.00 70.00 50.00 30.00 20.00 10.2 103 10.4 11.40 14.00 18.20 20.2 24.5 27.0 31. 2 34.2 35.8 - 13.00 .95 7.91 9 .17 10.15 X 12.00 4.27 TL 11.50 1) Using Excel, or some other graphing program (or by hand), make a graph of Image Distance vs. Object Distance (q...
A Lens and a Mirror In the figure below a converging lens is located at 0 cm. It has a focal length of f1 = 20.2 cm. An object is placed at a = 25.2 cm to the left from the converging lens. In addition a concave mirror with focal length of f2 = 10.4 cm is located L = 117.21 cm to the right of the lens. 1) Give your final answers in a coordinate system which has its...
Consider an object, an image and a lens. Think about how to place the object, image and lens such that the magnification is M = +1.5 and that the image is located 30 cm from the lens. What is the focal length of the lens that you must use? (Hint: First draw out possible scenarios before to decide on the best relative placements before attempting to find f.)
A converging lens creates the image shown in: Is the object distance less than the focal length f, between f and 2f, or greater than 2f?
You are provided a convex (+) thin lens and an object where a real image at a focal length f=f is found. Find the minimum distance possible from the object to the image using the focal length. Draw a ray sketch and use the thins lens equation.
Use the thin lens equation to solve problems 14 –18. 14. An object is 10 cm high and is placed 20 cm in front of a converging lens of focal length 20 cm. Determine the image distance, the image height and the magnification. 15. An object is 10 cm high and is placed 16 cm in front of a converging lens of focal length 20 cm. Determine the image distance, the image height and the magnification. 16. An object is...
Part A: Investigation of lens behaviors using a distant object Go to a room that has an outside window. With only the windows cracked open and all other lights off, use the reading glasses (or, more easily, the magnifying glass) and see if you can capture the light of something outside the window (perhaps a tree, or a light post or anything you can see outside the window) and “project” the captured light on to a screen (this screen can...