Question

please answer all parts asap i will rate thumbs up

Problem 1: 10 Points Link 3, shown schematically in the figure, acts as a brace to support the 300-1bf load applied at the pin at B. It is inclined at angle = 60° with the horizontal. Both links 2 and 3 have a rectangular cross section with 2 in. width. The material used for both links 2 and 3 is a hot-rolled SAE 1018 steel. (a) Assuming a factor of safety of 3.5, specify the minimum thickness of link 3 so that it does not fail by buckling. For buckling in the plane of the figure, the link may be regarded as pinned at both ends. For out-of-plane buckling, the ends are fixed. (b) If link 2 has the same thickness as link 3, what will be the factor of safety for yielding in link 2? F = 300 lbf

Answer 1

are forces in link len Tet f f f respectively. 0 - GO If > 300 lbf=F. using Lami's theorm = = F Singo f Sin (90+0) Sin (180-0) F = 300 x Sin 120 =519.61 lb f Sin iso F = 300 = 600 lif singo Siniso link 3 is subjected to F axial compressive load using Euler's theory F = T2E I min le ². (FOS) for hot rolled SAE 1018 Tyr = 53700 Ps E = 29700 KSI width=6= 2 in let thickness - t

Imin = bes - 2t3 = 1 deryth of link le=s=5 = 5.77 ft Santo Sino since SIA Fos= factor of party = 3.5 using equation o 600 = 72 x 29700 x 103 x 3 - 12²x8.772 X 3.5 6. x=8X124 [t=0.5a inch. I yielding load for link 2. F = Tyf XA = Typ X y bxt F = 53700 x 2 x 0.59 = 634 37.65 lb fador of safty (fos) = € = 63437-65 519.61 fos = 122 Note link as it is subjected will not buckle to tensile load